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andre [41]
3 years ago
9

I know the paper is blurry but can anyone explain any of the questions from 76-80?

Chemistry
1 answer:
Whitepunk [10]3 years ago
3 0

Answer:try to make a good pic please I have ideas about the topic

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The scientific method is great, but how do you think we answer the questions which cannot be tested with an experiment?
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Answer:

We do something called hypothesis

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Which group on the periodic table contains only metals?
Snezhnost [94]

Answer: GROUP  2 is the only group to include only metals. Group one includes the most metalic metals but hydrogen is usually put into group one and obviously hydrogen is not a metal. Group 2 includes Br, Mg, Ca, Sr, Ba,Ra.

Explanation:

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The energy necessary for photosynthesis to take place is provided by
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The Sunlight

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Heat in soi

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The center on your school’s basketball team is 6 ft 10 in tall. How tall is the player in millimeters (mm)?
svp [43]

The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Given,

The center of the school's basketball team is 6 ft 10 inches tall.

We have to convert the height of the player from feet and inches to feet.

Using the conversion factor,

1 ft = 12 inches

or, 12inches/ 1 ft

Converting 6ft 10 inches to ft, we get;

10 inches × 1 ft/ 12inches

= 0.833 ft

Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870

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5 0
1 year ago
A fossil was analyzed and determined to have a carbon-14 level that is 70 % that of living organisms. The half-life of C-14 is 5
Citrus2011 [14]

Answer: 2948

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{5730}=1.21\times 10^{-4}years^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}years^{-1}

t = age of sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = \frac{70}{100}\times 100=70

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{70}

t=2948years

Thus the fossil is 2948 years old.

5 0
3 years ago
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