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tangare [24]
3 years ago
13

Calculate the new volume if in a container there is a mass of gas that occupies a volume of 1.3L at a temperature of 280K. Calcu

late the volume when reaching a temperature of 303K.
Chemistry
1 answer:
USPshnik [31]3 years ago
6 0

Answer:

1.4 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 1.3 L

Initial temperature (T1) = 280 K

Final temperature (T2) = 303 K

Final volume (V2) =?

With the above data, we can obtain the new volume of the gas by using the Charles' law equation as shown below:

V1 /T1 = V2 /T2

1.3/280 = V2 /303

Cross multiply

280 × V2 = 1.3 × 303

280 × V2 = 393.9

Divide both side by 280

V2 = 393.9/280

V2 = 1.4 L

Thus, the new volume of the gas is 1.4 L

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Explanation:

Adhesion means the ability to stick on the surface of another substance.

Water exhibits adhesive forces due to which it is able to stick to the glass.  Due to adhesive forces water spreads over the surface of glass and sticks to it.

These adhesive forces between the glass and water enough that it deforms the spherical shape of water molecules and help them stick to the surface of glass. As a result, adhesive forces overcome the repulsion between like molecules.

Hence, water is able to “stick” to the side of glass due to strong adhesive forces.


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3 years ago
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How many molecules of excess reactant remain after the reaction is complete?
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Why is it necessary to use clean sponge and cleaning rags in dishwashing?​
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Answer:

cloths/sponges can harbor harmful pathogens and spread germs if not cleaned frequently. A damp, smelly dish cloth/sponge is telling you germs are multiplying!

Explanation:

hope this is able to help you :)

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2 years ago
Which of the following statements is true?
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The correct answer is C. Atoms are incredibly small and can bearly be seen with the most powerful electron microscopes. The nucleas of an atom contains protons and neutrons with electrons in orbitals around the nucleas. I hope this helps. Let me know if anything is unclear.
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2 years ago
Classify each of the following compounds as a strong acid, weak acid, strong base, or weak base, and write the Ka expression for
Katyanochek1 [597]

Answer:

See explanation below

Explanation:

There are several ways to know if an acid or base is strong. One method is calculating the pH. If the pH is really low, is a strong acid, and if it's really high is a strong base.

However we do not have a pH value here.

The other method is using bronsted - lowry theory. If an acid is strong, then his conjugate base is weak. Same thing with the bases.

Now, Looking at the 4 compounds, we can say that only two of them is weak and the other two are strong compounds. Let's see:

LiOH ---> Strong. If you try to dissociate :

LiOH ------> Li⁺ + OH⁻     The Li⁺ is a weak conjugate acid.

HF -----> Weak

HF --------> H⁺ + F⁻   The Fluorine is a relatively strong conjugate base.

HCl -----> Strong

This is actually one of the strongest acid.

NH₃ ------> Weak

Now writting the Ka and Kb expressions:

Ka = [H⁺] [F⁻] / [HF]

Kb = [NH₄⁺] [OH⁻] / [NH₃]

Finally, to calculate the [OH⁻] we need to use the following expression:

Kw = [H⁻] [OH⁻]

Solving for [OH⁻] we have:

[OH⁻] = Kw / [H⁺]

Remember that the value of Kw is 1x10⁻¹⁴. So replacing:

[OH⁻] = 1x10⁻¹⁴ / 7x10⁻⁶

[OH⁻] = 1.43x10⁻⁹ M

And now, multiplying by 10¹⁰ we have:

[OH⁻] = 1.429x10⁻⁹ * 1x10¹⁰

<h2>[OH⁻] = 14.29 </h2>

Hope this helps

4 0
2 years ago
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