Answer:
c) .51835
Explanation:
Let the relative abundance of the lighter of the two isotopes be X we have
Then the relative abundance of the heavier isotope is then (1-X)
Whereby we have that in nature the amount of the lighter silver found in proportion is X and the heavier isotope of silver is present as (1-X) proportion in nature.
To calculate the relative atomic mass of silver, we have
(Mass of light weight silver)×X + (mass of heavier isotope of silver×(1-X) = relative atomic mass of silver
106.90509(X) + 108.9047(1-X)
108.9-108.9(x)+106.9(x) = 107.87
-2x-1.03 = 0.517450902926
Closest answer is c
c) .5184
The relative atomic mass of isotopes is the weighted average by the mole-fraction of abundance of these isotopes which gives the atomic weight that is listed for that element on the periodic table.
Answer
1. 1cm=10mm, 1kg=1000g and 12in=1 ft
2. 50mm=5cm
48 in =4ft
36ft=12 yd
2.5m=250cm
1000mL= 1 L
Explanation
if 1cm=10mm then 5cm=?
5×10=50mm
if 12 in =1ft then 48in=?
48/12 =4 ft
if 1m=100cm, then 2.5m=?
2.5×100= 250cm
and when know from capacity that 1000mL is equivalent to 1 liter.
Answer:
The critical temperature of a substance is the temperature at and above which vapour of the substance cannot be liquefied, no matter how much pressure is applied.
