Answer:
speed = wavelength * frequency
Explanation:
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Answer: Quantum programming is the process of assembling sequences of instructions, called quantum programs, that are capable of running on a quantum computer. Quantum programming languages help express quantum algorithms using high-level constructs.
Explanation:
Answer:
Explanation:
Work done by the person depends on its mass and the height raised. It also depends on the acceleration due to gravity.
As the height raised and the mass of person is same. The value of acceleration due to gravity is also constant So, the work done is also same in both the cases.
Answer:
1. 80,000 Pa
2. 11.3 m/s
3. 12.5 m/s
Explanation:
<u>Question 1</u>
Pressure, 
Where h is the height that water is to reach, g is gravitational constant and 
is the density, in this case, we assume of pure water as 
Assuming 
P=8*10*1000=80000 Pa
<u>Question 2</u>
Pressure can also be found by the formula
where v is the velocity
Equating the new formula of pressure to the formula used in question 1 above
Notice that is common hence
Making V the subject of the formula
In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}
Rounding off to 1 decimal place
v=11.3 m/s
<u>Question 3</u>
As already illustrated
Taking g as 9.8 and h now is 8m
v=12.52198067
Rounding off to 1 decimal place
v=12.5 m/s
Answer:
A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm
, this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.
we have a fluctuation of the intensity emitted by the stars. Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.
Explanation:
The radiation of a black body is characterized by its temperature, with Wien's law of displacement we can find the maximum wavelength emitted by each star.
λ T = 2,898 10⁻³
therefore the emission the star of A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm
The emission of the premiere is in the ultraviolet light range, as this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.
The burst with A = 4300K has a bad emission maximum = 6.7395 10⁻⁷ m = 673.95 nm, which corresponds to an emission in the visible in the orange range, giving a blackbody spectrum of this range, but since the emission is formed by two stars, we see that when the two are placed one in front of the other the intensity of the emission must increase significantly and when they are placed next to each other the intensity reaches its minimum, consequently we have a fluctuation of the intensity emitted by the stars.
Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.
