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balu736 [363]
3 years ago
11

To increase the brightness of a desk lamp, a student replaces a 50-watt incandescent lightbulb with a 100-watt incandescent ligh

tbulb. Compared to the 50-watt lightbulb, the 100-watt lightbulb has (1) less resistance and draws more current (2) less resistance and draws less current (3) more resistance and draws more current (4) more resistance and draws less current
Physics
1 answer:
swat323 years ago
3 0
From the formula for Electric Power, P = IV,    P = V²/R

So the 100W compared to the 50W.

From P = IV. From the equation there is a direct relationship between P and I.  More  Power P means more Current, I.

From P = V²/R. From the equation, there is an inverse relationship
between P and R. Therefore  more P means less R. 

So from these assertions, the answer is: 

(1) less resistance and draws more current
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A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the hori
vladimir2022 [97]

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

  • The horizontal component of the pulling force, F cos \theta, where F = 50 N is the magnitude and \theta=60^{\circ} is the angle between the direction of the force and the horizontal; this force acts in the  forward direction
  • The force of friction, F_f, acting in the backward direction

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

\sum F_x = ma_x

where

m is the mass of the block

a_x is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

a_x = 0

So the equation becomes

\sum F_x = 0 (1)

The net force here is given by

\sum F_x = F cos \theta - F_f (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N

Learn more about  force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

4 0
3 years ago
The image below shows four points on the orbit of a comet around the Sun.
Firlakuza [10]

Answer:

<u>Point </u><u>A</u>

Explanation:

And the strongest force of gravity is point C

3 0
3 years ago
In need help I need someone that is really good at physics
Aloiza [94]
10/70×360°
=51.4°

hope thus helps
5 0
4 years ago
The space shuttle orbits 310 km above the surface of the Earth.
MAVERICK [17]

Answer:

44.7 N

Explanation:

The gravitational force between the objects is given by:

F=G\frac{mM}{r^2}

where

G is the gravitational constant

m and M are the masses of the two objects

r is the distance between the centres of the two objects

In this problem, we have:

m=5.0 kg is the mass of the sphere

M=5.98\cdot 10^{24} kg is the Earth's mass

R=6370 km is the Earth's radius, while h=310 km is the altitude of the sphere, so the distance of the sphere from Earth's centre is

r=6370 km+310 km=6680 km=6.68\cdot 10^6 m

Substituting into the equation, we find

F=(6.67\cdot 10^{-11})\frac{(5.0 kg)(5.98\cdot 10^{24} kg)}{(6.68\cdot 10^6 m)^2}=44.7 N

8 0
3 years ago
Plane-polarized light is incident on a single polarizing disk, withthe direction of E0 parallel to thedirection of the transmiss
Alenkinab [10]

Answer;

Cos²စ= I/Io

So

A. Cos²စ = 1/2.2

Cosစ= √1/2.2

စ = cos^-1 0.68

= 47.2°

B.

Cosစ = √1/5.2

စ = ,cos^-1 0.4385

= 64°

C.

Cosစ = √1/12

စ = cos^-1 0.2886

= 73.2°

6 0
3 years ago
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