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WARRIOR [948]
3 years ago
14

What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?

Physics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

\tan\theta=\dfrac{v^2}{rg}

v=\sqrt{rg\tan\theta}

Put the value into the formula

v=\sqrt{85\times9.8\tan15}

v=14.9\ m/s

We need to calculate the minimum coefficient of friction

Using formula for coefficient of friction

v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}

Put the value into the formula

(5.55)^2=\dfrac{85\times9.8(\sin15-\mu\cos15)}{\mu\sin15+\cos15}

\dfrac{30.8025}{85\times9.8}=\dfrac{0.2588-\mu0.966}{\mu0.2588+0.966}

0.9754462\ mu-0.223541=0

\mu=\dfrac{0.223541}{0.9754462}

\mu=0.22

Hence, The minimum coefficient of friction is 0.22

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We are asked to solve and determine the magnitude of the current flowing through the first device. In order for us to have a better understanding of the problem, we can refer to the attached picture which contains electric circuit diagram. Since it the problem we are already given with an electromotive source or the voltage supply and since the two resistance is in parallel, it would clearly mean that the voltage drop in each resistance is just the same. The resistance 1 uses the 40 volts at the same time the resistance 2 uses 40 volts also. Solving further for the current, we can apply Ohm's law which V = IR where "V" represents the voltage, the "I" represents the current and "R" represents the resistance.

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Answer:

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From the question given above, the following data were obtained:

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