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faust18 [17]
3 years ago
5

A block of mass 21 kg slides up a frictionless plane inclined at 13◦ with the horizontal under the influence of a force of 210 N

acting parallel to the incline and up the incline. The acceleration of gravity is 9.8 m/s 2 . What is the acceleration of the block? Answer in units of m/s 2 .
Physics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

a= 8.74 m/s²

Explanation:

Given that

m = 21 kg

θ = 13◦

F= 210 N

g= 9.8 m/s²

The force due to gravity

F₁= m g sinθ

F₁=12 x 9.8 x sin 13◦

F₁=26.45 N

Lets take acceleration is a  m/s²

Form Newtons second law

F - F₁ = m a

210 - 26.45 = 21 x a

a= 8.74 m/s²

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Answer:

2.44156\times 10^{13}\ m^3

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Explanation:

\rho = Density of asteroid = 2 g/cm³

V = Volume

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v = Velocity = 11 km/s

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Mass is given by

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The kinetic energy is

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Heat is given by

Q=mc\Delta T+mH_v\\\Rightarrow 6.33556\times 10^{22}=m\times (4186\times (100-20)+2.26\times 10^6)\\\Rightarrow m=\dfrac{ 6.33556\times 10^{22}}{4186\times (100-20)+2.26\times 10^6}\\\Rightarrow m=2.44156\times 10^{16}\ kg

Mass of water is 2.44156\times 10^{16}\ kg

Volume is \dfrac{2.44156\times 10^{16}}{10^3}=2.44156\times 10^{13}\ m^3

Amount of water is 2.44156\times 10^{13}\ m^3

If it were a cube

h=V^{\dfrac{1}{3}}\\\Rightarrow h=(2.44156\times 10^{13})^{\dfrac{1}{3}}\\\Rightarrow h=29010.53917\ m

The height of the water would be 29010.53917 m

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Pure water boils at  100°C  and freezes at O°C ,

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Molecular formula brainly.com/question/4574324

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