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faust18 [17]
3 years ago
5

A block of mass 21 kg slides up a frictionless plane inclined at 13◦ with the horizontal under the influence of a force of 210 N

acting parallel to the incline and up the incline. The acceleration of gravity is 9.8 m/s 2 . What is the acceleration of the block? Answer in units of m/s 2 .
Physics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

a= 8.74 m/s²

Explanation:

Given that

m = 21 kg

θ = 13◦

F= 210 N

g= 9.8 m/s²

The force due to gravity

F₁= m g sinθ

F₁=12 x 9.8 x sin 13◦

F₁=26.45 N

Lets take acceleration is a  m/s²

Form Newtons second law

F - F₁ = m a

210 - 26.45 = 21 x a

a= 8.74 m/s²

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<h3>What is magnetic moment?</h3>

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Calculations:

radius= 5.29 * 10^{-11} m\\

velocity=2.9* 10^{6} m/s

Working formula, M=N/A

I=\frac{charge flow }{time taken} =\frac{e}{time taken\\}

T= \frac{2xr}{v} =\frac{2xx * 5.29 * 10^{-11} }{2.9* 10^{6} }

   =15.16 * 10^{-5} s

I= \frac{1.6 * 10^{-19} }{15.16 * 10^{-5} }= 0.10 * 10^{-14}

                     =1 * 10^{-15} C

M=1x (1* 10^{-15} * (5.29 * 10^{-11} )^{2}

  =87.87 * 10^{-37}

To learn more about magnetic moment ,visit:

brainly.com/question/14298729

#SPJ4

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A e limb of mass 12kg falls straight down. If air resistance exerts 27 N of froce on the limb as it falls, what is the net force
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