The tension in the string supporting the rod and the attached weights is 7.11 N.
<h3>Tension in the string supporting the rod</h3>
The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.
T = (m1 + m2)g
where;
- m1 and m2 are the two masses supported
0.4lb + 1.2lb = 1.6lb = 0.725 kg
T = 0.725 x 9.8
T = 7.11 N
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There all diffrent speeds
Answer:
Velocity = 0.105m/s
Explanation:
Using conservation of momentum:
Momentum before impact= mass of ball × velocity of ball
= 0.400×10.8= 4.32
Momentum after impart= mass of ball × velocity of ball + mass of olaf × velocity of olaf
= 4.35 +3.56 + 74.9Vf
Vf=7.88_74.9 = o.0.105m/s
Hey again!
Ok..
Now... The melting Point of this solid is 90°C.
Meaning That as soon as it gets to this temp... It STARTS Melting.
So at that temp... It still has some solid parts in it.
You can say its a Solid Liquid Mixture.
Additional Heat being applied at that point is not raising the temperature;rather its used in breaking the bonds in the solid. This is the Fusion stage.
After Fusion...It'd then Be a Pure Liquid with no solids in it.
So
Q'=MC∆0----- This is the heat needed to take the solid's temp from 30°c - 90°c
Q"=ml ----- This is the heat used in breaking the bonds holding the solids in the solid-liquid phase.
So
Q= Q' + Q"
Q= mc∆0 + ml
∆0 = 90°c - 30°c = 60°c
Q= 2.5(390)(60) + (2.5)(4000)
Q=6.9 x 10⁴Joules
Answer:
4
Explanation:
2*2
www.omnicalculator.com/physics/wavelength
