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mestny [16]
3 years ago
14

A baby sloth weighed 2.95 pounds when born. After a six months, the sloth was three times heavier than it was at birth. How much

did the sloth weigh after six months?
Mathematics
1 answer:
Igoryamba3 years ago
7 0

Answer:

8.85 pounds

Step-by-step explanation:

Weight at birth = 2.95 pounds

After a six months, the sloth was three times heavier than it was at birth

New weight after six months = 3 × weight at birth

= 3 × 2.95 pounds

= 8.85 pounds

New weight after six months = 8.85 pounds

The sloth weighs 8.85 pounds after six months

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The Perimeter Of A Rectanglular Garden Is 84 Feet . The Length Of The Garden Is Twice The Width . What Is The Width Of The Garde
nalin [4]
\bf \stackrel{\textit{perimeter of a rectangle}}{P=2L+2W\implies 2(L+W)}~~
\begin{cases}
L=length\\
W=width\\
--------\\
P=84\\
L=\stackrel{\textit{twice the width}}{2W}
\end{cases}
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84=2(L+W)\implies \cfrac{84}{2}=L+W\implies 42=L+W
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4 years ago
Jordan is another employee at the same coffee shop. He has worked there longer than Gabe and earns $3 more per hour than Gabe. C
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3 years ago
What is the value of the expression x + (–y) when x = –2.3 and y = –5.9? A. –8.2 B. –3.6 C. 3.6 D. 8.2
11Alexandr11 [23.1K]
Now it would be
-2.3+(-5.9)

now just add those two together
and u get -8.2
So the answer is A
7 0
3 years ago
Select the correct answer from each drop-down menu. A parabola is given by the equation y = x2 − 2x − 3. The directrix of the pa
choli [55]

Answer:

Part 1) The directrix of the parabola is y=-4.25

Part 2) The focus of the parabola is F(1,-3.75)

Step-by-step explanation:

we have

y=x^{2}-2x-3

This is a vertical parabola open upward

we know that

If a parabola has a vertical axis, the standard form of the equation of the parabola is

(x - h)^{2}=4p(y - k)

where

p≠ 0

The vertex of this parabola is at (h, k).

The focus is at (h, k + p).

The directrix is the line y = k - p.

The axis is the line x = h.

step 1

Convert the equation of the parabola in standard form

y=x^{2}-2x-3

y+3=x^{2}-2x

y+3+1=x^{2}-2x+1

y+4=x^{2}-2x+1

y+4=(x-1)^{2}

so

(x-1)^{2}=(y+4) ----> equation in standard form

The vertex is the point (1,-4)

4p=1 ------> p=1/4

step 2

Find the directrix of the parabola

The directrix is the line y = k - p

we have

k=-4

p=1/4

substitute the values

y = k - p

y=-4-(1/4)=-17/4

y=-4.25

step 3

Find the focus of the parabola

we know that

The focus is at (h, k + p).

we have

h=1

k=-4

p=1/4

substitute

F(1,-4+1/4)

F(1,-3.75)

4 0
3 years ago
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