The element is TELLURIUM. Tellurium has atomic number 52 with the electronic configuration of [Kr] 4d10 5s2 5p4. The element belongs to group 16 elements on the periodic table. It exhibits various oxidation states: +2, +4, +6, and -2. +4 is its most common oxidation state.
write an equation to represent the oxidation of an alcohol.
identify the reagents that may be used to oxidize a given alcohol.
identify the specific reagent that is used to oxidize primary alcohols to aldehydes rather than to carboxylic acids.
identify the product formed from the oxidation of a given alcohol with a specified oxidizing agent.
identify the alcohol needed to prepare a given aldehyde, ketone or carboxylic acid by simple oxidation.
write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.
The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.
This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.
Oxidizing the different types of alcohols
The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is
Cr2O2−7+14H++6e−→2Cr3++7H2O
Explanation:
The given data is as follows.
Concentration = 3.3 mol
Rate constant = 
Molecular weight = 55000 g/mol
Initial concentration (
) of aminoheptanoic is 3.3 kg/mol.
Hence, putting the given values into the above formula as follows.
= ![\frac{3.3}{2.74 \times 10^{3} kg/mol min} [X_{A}]^{0.1}_{0}](https://tex.z-dn.net/?f=%5Cfrac%7B3.3%7D%7B2.74%20%5Ctimes%2010%5E%7B3%7D%20kg%2Fmol%20min%7D%20%5BX_%7BA%7D%5D%5E%7B0.1%7D_%7B0%7D)
= 120.43 min
Thus, we can conclude that total time required to to form polyamide is 120.43 min.
When atoms share six electrons, they are joined by a double bond. (.5 points)
a. True
b. False?
Is False
Answer:
A transition metal
Explanation:
The metal is classified as a transition metal or transition element.
In particular, this atom is Copper it has an atomic number of 29 which we know by the number of protons.
The number of protons in an atom is the same as the atomic number.
- The element can be found in the d-block on the periodic table.
- Generally, it is classified as a transition metal.
- A neutral atom of this element has 29 electrons.
