Answer:
1.38x10⁻⁴ M
Explanation:
First, we <u>calculate the pOH of the solution</u>, using the <em>given pH</em>:
Now we <u>calculate the concentration of OH⁻</u>, using<em> the pOH</em>:
- [OH⁻] =
= 2.75x10⁻⁴ M
Following the reaction Ca(OH)₂ → Ca⁺² + 2OH⁻, we divide [OH⁻] by 2 to calculate [Ca(OH)₂]:
- [Ca(OH)₂] = 2.75x10⁻⁴ M / 2
2 is the correct answer because with 2O2 molecules it balances the chemical equation.
Hope that helps
A) C2H6O1
To find the emperical formula, divide each mole value by the smallest
For carbon, 0.013/0.0065 = 2
For hydrogen, 0.038/0.0065= 6
For oxygen, 0.0065/0.0065= 1
Emperical formula = C2H6O1
This is an incomplete question, here is a complete question.
Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.
CaCO₃, Ksp = 8.7 × 10⁻⁹
Answer : The solubility of CaCO₃ is, 
Explanation :
As we know that CaCO₃ dissociates to give
ion and
ion.
The solubility equilibrium reaction will be:

The expression for solubility constant for this reaction will be,
![K_{sp}=[Ca^{2+}][CO_3^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BCO_3%5E%7B2-%7D%5D)
Let solubility of CaCO₃ be, 's'




Therefore, the solubility of CaCO₃ is, 