Answer:
Ratio of [CO₃²⁻] / [H₂CO₃] is 1.0x10⁻⁸
Explanation:
Based on the equilibriums:
H₂CO₃ ⇄ H⁺ + HCO₃⁻ Ka1 = 4.3x10⁻⁷
HCO₃⁻ ⇄ H⁺ + CO₃²⁻ Ka2 = 4.8x10⁻¹¹
The sum of both equilibriums is:
H₂CO₃ ⇄ 2 H⁺ + CO₃²⁻ K' = 4.3x10⁻⁷*4.8x10⁻¹¹ = 2.064x10⁻¹⁷
Where K' is defined as:
K' = 2.064x10⁻¹⁷ = [H⁺]² [CO₃²⁻] / [H₂CO₃]
If concentration of H⁺ is 4.5x10⁻⁵M:
K' = 2.064x10⁻¹⁷ = [4.5x10⁻⁵]² [CO₃²⁻] / [H₂CO₃]
1.0x10⁻⁸ = [CO₃²⁻] / [H₂CO₃]
Thus, <em>ratio of [CO₃²⁻] / [H₂CO₃] is 1.0x10⁻⁸</em>
Answer:
(d) has an extremely large equilibrium constant.
Explanation:
Hello,
Considering a generic chemical reaction:
The equilibrium constant is defined as:
![K=\frac{[C]^c_{eq}[D]^d_{eq}}{[A]^a_{eq}[B]^b_{eq}} \\](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BC%5D%5Ec_%7Beq%7D%5BD%5D%5Ed_%7Beq%7D%7D%7B%5BA%5D%5Ea_%7Beq%7D%5BB%5D%5Eb_%7Beq%7D%7D%20%5C%5C)
Now, an irreversible chemical reaction is a reaction in which the reagents are converted into products with no chance of coming back, so, considering the previous chemical reaction, the concentration of both A and B tends to be zero, so an extremely large equilibrium constant is gotten.
Best regards.
Answer:
1.23 j/g. °C
Explanation:
Given data:
Mass of metal = 35.0 g
Initial temperature = 21 °C
Final temperature = 52°C
Amount of heat absorbed = 320 cal (320 ×4.184 = 1338.88 j)
Specific heat capacity of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 52°C - 21 °C
ΔT = 31°C
1338.88 j= 35 g ×c× 31°C
1338.88 j= 1085 g.°C ×c
1338.88 j/1085 g.°C = c
1.23 j/g. °C = c
Explanation:
what i would think is when u spray your air freshener it sprays molecules of that freshener the molecules dont just spray and go down there it spreads around the room and some of those molecules also enter ones nose and that is why he smells the freshener
i hope this is helps
No, if H2O is separated into H2 and O, then it is not the same substance
