Answer:
For f(x) to be differentiable at 2, k = 5.
Step-by-step explanation:
For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.
For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.
Now,
f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.
As h tends to 0, lim (5 – 2h) = 5
Also
f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h
As h tends to 0, lim (5 + 3h) = 5.
So, for f(2) to be continuous k = 5
D a theorem needs to be proven
2193 x 10(little 37) over 79
or
≈2.77595 x 10(little 38)
Answer:1/9(x+0.1)
Step-by-step explanation:
1/9x+10/9
=1/9(x+0.1)
Answer:
Should be 1/7
Step-by-step explanation:
I just measured it.
