What is 607-568 rounded off to the nearest 100
1 answer:
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Answer:
Elements are of the form
(i)
(ii)
(iii)
(iv)
(v) (a,b) where a>b=
(vi) [a,b] where a>b=
Step-by-step explanation:
Given intervals are,
(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi) [a,b] where a>b.
To show all its elements,
(i) [a,a]
Imply the set including aa from left as well as right side.
Its elements are of the form.
Since there is a singleton element a of real numbers, this set is empty.
Because there is no increment so if then the set [a,a] represents singleton sets, and singleton sets are empty so is [a,a].
(ii) [a,a)
This means given interval containing a by left and exclude a by right.
Its elements are of the form.
Since there is a singleton element a of real numbers withis the set, this set is empty.
Because there is no increment so if then the set [a,a) represents singleton sets, and singleton sets are empty so is [a.a).
(iii) (a,a]
It means the interval not taking a by left and include a by right.
Its elements are of the form.
Since there is a singleton element a of real numbers, this set is empty.
Because there is no increment so if then the set (a,a] represents singleton sets, and singleton sets are empty so is (a,a].
(iv) (a,a)
Means given set excluding a by left as well as right.
Since there is a singleton element a of real numbers, this set is empty.
Its elements are of the form.
Because there is no increment so if then the set (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).
(v) (a,b) where a>b.
Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.
That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,
e.t.c
So this set is connected and we know singletons are connected in . Hence given set is empty.
(vi) [a,b] where .
Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.
That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,
e.t.c
So this set is connected and we know singletons are connected in . Hence given set is empty.
Answer:
936 jars of peanut butter contain less peanut butter than usual.
Step-by-step explanation:
1. First, we need to find how many jars of peanut butter that contain less peanut butter than advertised are produced every hour.
The factory produces 1200 jars of peanut butter every hour
3.25% of those jars have less peanut butter than advertised
So: multiply (the decimal form of the percent) to find the amount of peanut butter jars that contain less peanut butter than advertised.
So the factory produces 39 jars of peanut butter that contain less peanut butter than advertised.
2. Second, we need to find how many jars of peanut butter that contain less peanut butter than advertised in three 8 hour work days.
Lets add these work days together to find the total amount of hours:
So: three 8 hour work days totals to 24 hours
Since the factory produces 39 jars of peanut butter that contain less peanut butter than advertised per hour. Multiply to find the total amount of jars produced in three 8 hour work days.
A total of 936 peanut butter jars are produced in three 8 hour work days that contain less peanut butter than advertised.
3. If you want to double check your work do the following.
Since the factory produces 1200 jars an hour and 24 hours total three 8 hour work days. Multiply
So there is a total of 28800 jars produced in three 8 hour work days.
Then you can multiply 28800 by 3.25% of jars that contain less peanut butter to find the total amount of peanut butter jars that contain less peanut butter in three 8 hour work days.
