Answer:
Explanation:
Heat capacity A = 3 x heat capacity of B
initial temperature of A = 2 x initial temperature of B
TA = 2 TB
Let T be the final temperature of the system
Heat lost by A is equal to the heat gained by B
mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)
heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)
3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB)
3 TA - 3 T = T - TB
6 TB + TB = 4 T
T = 1.75 TB
Answer:
1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Explanation:
1st: Theatre History
4th Quarter
Upcoming
Due today
Syllabus
Due Sunday
Answer:
Explanation:
(a) the angle between the coil and the coil's magnetic dipole moment is same that means zero degree.
(b) L = 17.6 cm = 0.176 m
i = 5.95 mA = 5.95 x 106-3 A
B = 4.74 mT = 4.74 x 10^-3 T
(b) Let r be the radius of the loop is r
Circumference = 2 x 3.14 x r
0.176 = 2 x 3.14 x r
r = 0.028 m
B = μo/4π x (N x 2 π i) / r
Where, N be the number of turns
4.74 x 10^-3 = (10^-7 x N x 2 x 3.14 x 5.95 x 10^-3) / 0.028
N = 3.55 x 10^4
(c) Maximum torque = N i A B
τ = 3.55 x 10^4 x 5.95 x 10^-3 x 3.14 x 0.028 x 0.028 x 4.74 x 10^-3
τ = 2.465 x 10^-3 Nm
Answer:
6.0 m below the top of the cliff
Explanation:
We can find the velocity at which the ball dropped from the cliff reaches the ground by using the SUVAT equation
where
u = 0 (it starts from rest)
g = 9.8 m/s^2 (acceleration of gravity, we assume downward as positive direction)
h = 24 m is the distance covered
Solving for h,
So the ball thrown upward is launched with this initial velocity:
u = 21.7 m/s
From now on, we take instead upward as positive direction.
The vertical position of the ball dropped from the cliff at time t is
While the vertical position of the ball thrown upward is
The two balls meet when
So the two balls meet after 1.11 s, when the position of the ball dropped from the cliff is
So the distance below the top of the cliff is
