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damaskus [11]
2 years ago
6

E) the time it takes the car to reach 20.0ms-1​

Physics
1 answer:
Galina-37 [17]2 years ago
8 0
4.2 thats the answer
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We reduce friction in machines? why<br>​
kvv77 [185]

Answer:

friction reduces the efficiency of machines, thus we must reduce the friction force that is acting upon it.

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13) A mass attached to the free end of a spring executes simple harmonic motion according to the equation y = (0.50 m) sin (18π
Kitty [74]

Hi there!

The period is given by:

T = \frac{2\pi}{w}

T = Period (sec)

w = angular frequency (rad/sec)

According to the equation for SHM in terms of position:

y(t) = Asin(ωt + φ)

A = Amplitude (m)

ω = angular frequency (rad/sec)

t = time (sec)

φ = phase angle

In this instance, the angular frequency is given as 18π.

Plug this value into the equation for T:

T= \frac{2\pi}{18\pi} = \frac{1}{9} = \boxed{0.111 s}

4 0
3 years ago
If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What
Pavel [41]

Answer: 1.54m^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 1 atm

P_2 = final pressure of gas = 2.67 atm

V_1 = initial volume of gas = 3.61m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas at STP = 0^oC=273+0=273K

T_2 = final temperature of gas = 37.9^oC=273+37.9=310.9K

Now put all the given values in the above equation, we get:

\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}

V_2=1.54m^3

Thus the final volume will be 1.54m^3

7 0
3 years ago
g A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is
oksian1 [2.3K]

Answer:

velocity of girl with respect  to surface of ice 1.154 m/s

Explanation:

Plank Mass , M = 150 kg

Girl Mass , m = 45 kg

velocity of the girl with resect to plank, v1 = 1.50 m/s

velocity of the plank + girl = v2

from the conservation of momentum

Momentum (plank+girl) = - momentum of the girl

(M+m)v2 = -mv1

v2 = -(45 kg)/(195 kg) * 1.50

v2 = -0.346 m/s

velocity of girl with respect  to surface of ice =

  v1+v2 = 1.50 + (-0.346) = 1.154 m/s

4 0
3 years ago
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