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Lunna [17]
3 years ago
15

I need help with finding these?

Physics
1 answer:
Alchen [17]3 years ago
6 0
I think 23 is b and 24 a?
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3. The soccer kicker kicks a 2 kg football with a force of 68 N. How fast will the ball accelerate down the field?
Katen [24]

Answer:

\boxed {\boxed {\sf m= 2 \ kg , \\a= 34 \ m/s^2,  \\\F= 68 \ N}}

Explanation:

The formula for force is:

F=m*a

If we rearrange the formula to solve for a (acceleration), the formula becomes

\frac{F}{m} =a

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².

The mass is 2 kilograms.

F=68 \ kg*m/s^2 \\m= 2\ kg

Substitute the values into the formula.

\frac{68 \ kg*m/s^2}{2 \ kg} =a

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).

\frac{68 \ m/s^2}{2}=a

34 \ m/s^2=a

The acceleration is<u> </u><u>34 meters per second squared.</u>

6 0
3 years ago
A block of mass 5 kg is descending with a constant velocity on an inclined plane at 30°. What is the value of the frictional for
sattari [20]

Answer:28.9N

Explanation:

F=UR R=mg R=5×10 R=50N

U=tan© U=Tan30 U=1/√(3)

F=UR F=1/√(3) ×50

F=28.9N

4 0
2 years ago
When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to ________?
pav-90 [236]

When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to contract in size. The gravitational forces becomes strong and cause the star to reduce in size. as the star contracts, the temperature of the star also rises since the heat is distributed inside smaller Volume now.

4 0
3 years ago
Read 2 more answers
A. praised
krok68 [10]

Answer:

14. scolded

15. supporter

16. i am not sure but I think it is removes

17. comfortable

18. outdated

19. drink

20. it can be fantastic or wealthy

8 0
2 years ago
Read 2 more answers
A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}

b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
2 years ago
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