Answer:
J.J. Thomson discovered <u><em>the electron</em></u> by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.
Explanation:
the answer is the underlined part of the answer section. I hoped this helped you a lot!! Study hard for whatever you are doing!!
Formula of the gravitational force between two particles:

where
is the gravitational constant
m1 and m2 are the masses of the two particles
r is their distance
(a) particle A
The gravitational force exerted by particle B on particle A is
to the right
The gravitational force exerted by particle C on particle A is
to the right
So the net gravitational force on particle A is
to the right
(b) Particle B
The gravitational force exerted by particle A on particle B is
to the left
The gravitational force exerted by particle C on particle B is
to the right
So the net gravitational force on particle B is
to the right
(c) Particle C
The gravitational force exerted by particle A on particle C is
to the left
The gravitational force exerted by particle B on particle C is
to the left
So the net gravitational force on particle C is
to the left
The answer is A, Cell. This is the basic structure of a cell.
Answer:
Explanation:
r(t) = A(cos wt i + sin wt f)
= A cos wt i + A sin wt j
x = A cos wt
y = A sin wt
radius r
r² = x² + y² ( This is equation of a circle with radius r )
= A² cos² wt +A² sin² wt
= A²
r = A
radius r = A
b )
speed = dr/dt
v = - Aw sinwt i + Aw coswt j
magnitude of velocity
I v I= Aw √(sin²wt + cos²wt)
= Aw ( constant )
acceleration
= dv / dt = - Aw² cos wt - Aw² sinwt
magnitude of acceleration
I a I = Aw²
= r w²
d ) centripetal force = m acceleration
m w² A
=