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Svetradugi [14.3K]
4 years ago
5

How to find the valency of a polyatomic ion?

Chemistry
1 answer:
Lemur [1.5K]4 years ago
3 0

The valencies of the constituent atoms are combined by the poly atomic ion, carbonate, has a formula of CO3 the valence state it is in of oxygen ions is -2 the periodic table group it’s in Group 16 the two to the left of Group 18, the noble gases: 16–18 = -2) and their are 3 oxygen atoms in the poly atomic ion, so the oxygen atoms contribute -6 to the valency of the poly atomic ion. The one carbon atom has a valency of 4+. The overall charge on the carbonate ion is -6 +4 = -2. So carbonate has a charge of -2.







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9.7 g

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A balloon inflated in a room at 300 ºC has a volume of 7.0 L. The balloon is then cooled to a temperature of 25.0 ºC. What is th
QveST [7]

Answer:

\huge\boxed{\sf V_2 =3.64 \ L}

Explanation:

<u>Given Data:</u>

Initial Volume = V_{1} = 7.0 L

Initial Temperature = T_{2} = 300 °C + 273 = 573 K

Final Temperature = T_{2} = 25.0 °C + 273 = 298 K

<u>Required:</u>

Final Volume = V_{2} = ?

<u>Formula:</u>

\displaystyle \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}  <u>[Charles Law] </u>

<u>Solution:</u>

Put the givens

\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}

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Which substance will form a solution with water? (Select all that apply.)
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3 0
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Read 2 more answers
Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and character
docker41 [41]

Answer:

Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)

2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)

Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)

Explanation:

We're given the following ions:

Fe^{2+}, Cr^{3+}, Ni^{2+}

Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.

Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:

Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)

Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:

2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)

Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide:

Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)

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3 years ago
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