1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexxandr [17]
3 years ago
12

Biological membranes are selectively permeable, allowing certain molecules to cross the membrane, but not others. Classify the m

olecules or ions depending on how they cross a biological membrane. Note that some of these examples may also utilize active transport to traverse a membrane. However, this question is limited to passive transport processes only. Match the followings with each others
a. Simple Diffusion
b. Facilitated Diffusion

1. steroid hormones
2. K+
3. N2
4. Glucose
Chemistry
1 answer:
ddd [48]3 years ago
3 0

Answer:

Following are the solution to these question:

Explanation:

Simple diffusion implies which molecules can move across a cell membrane instead of using the incorporated protein structure channels. Its flow of molecules across these canals is enabled by diffusion. It has steroid hormones and N2.

Facilitated diffusion of molecules via cell membranes, or active transportation, which would be the random mass transit process of molecules or ions via unique cellular membranes from the transmembrane. It has K+ and Glucose.

You might be interested in
Consider the reaction: 2clf3(g) + 2nh3(g) → n2(g) + 6hf(g) + cl2(g) when calculating the δh°rxn, why is the δhf° for n2 not impo
Leni [432]

<span>Actually, the heat of reaction hrxn s calculated by taking the sum of the heats of formation of the products minus the sum of the heats of formation of the reactants. However, at heat of formations of pure elements at atmospheric conditions is zero, therefore the hf of N2 is not important since it is zero anyway.</span>

8 0
3 years ago
What is the periodic table a list of
barxatty [35]

Answer:

i think c should be ur answer

5 0
2 years ago
Why is it important to have the correct bond angles of the different atoms and the shape of the molecule? (20 points NEED ANSWER
hjlf

It is important to have the correct bond angles of the different atoms and the shape of the molecule due to following reasons;

                  Among other properties the polarity of compounds mainly depend upon the shape and bond angles of that particular compound. For example, considering the molecule of water, we already know that it is a polar molecule with partially positive hydrogen atoms and partially negative oxygen atoms and acts as universal solvent. The bond angle in water is about 104.5° with a Bent geometry. Unlike carbon dioxide (CO₂) which has Linear structure with bond angle 180° and is non-polar in nature therefore, the bent geometry in water is responsible for the polarity.

                  Other properties which can also be predicted by predicting the bond angles along with molecular geometries are;

                                      i) Magnetism

                                      ii) Phase of matter

                                       iii) Color

                                      iv) Reactivity

                                       v) Biological activities <em>e.t.c</em>

                     

5 0
3 years ago
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

3 0
3 years ago
Whats the name of S4O6
IceJOKER [234]

Answer:

Sulfonic acid

Explanation:

I think this is correct

8 0
3 years ago
Read 2 more answers
Other questions:
  • how many moles of CO2 form when 58.0 g of butane, C4H10, burn in oxygen? 2C4H10+13O2---&gt;8CO2+10H2O
    9·2 answers
  • What type of substance is soda?
    14·1 answer
  • How many moles are in 22 grams of argon?
    10·1 answer
  • Which of the following correctly shows a neutralization reaction between a hydronium ion and a hydroxide ion?
    11·2 answers
  • Give the formula of a compound in unpolluted air
    11·1 answer
  • _________based on religious beliefs
    6·1 answer
  • I need the answer step by step please
    11·1 answer
  • Identify the number of valence electrons in each atom:<br> a. Calcium <br> b. Carbon <br> c. Sulfur
    13·2 answers
  • Which of the following elements have the stronger attraction in a covalent bond with hydrogen, c, Na, O or S?
    5·1 answer
  • What is kept the same in a controlled experiment
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!