Answer:
![\overrightarrow {AB} = (4,5,6)](https://tex.z-dn.net/?f=%5Coverrightarrow%20%7BAB%7D%20%3D%20%284%2C5%2C6%29)
1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F
2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F
3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T
4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F
5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F
Step-by-step explanation:
The vector AB is the vectorial difference between point A and B, that is:
![\overrightarrow {AB} = \vec B - \vec A](https://tex.z-dn.net/?f=%5Coverrightarrow%20%7BAB%7D%20%3D%20%5Cvec%20B%20-%20%5Cvec%20A)
Given that
and
, the vector AB is:
![\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)](https://tex.z-dn.net/?f=%5Coverrightarrow%20%7BAB%7D%20%3D%20%283%2C-2%2C9%29-%28-1%2C-7%2C3%29)
![\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAB%7D%20%3D%20%283-%28-1%29%2C-2-%28-7%29%2C9-3%29)
![\overrightarrow {AB} = (4,5,6)](https://tex.z-dn.net/?f=%5Coverrightarrow%20%7BAB%7D%20%3D%20%284%2C5%2C6%29)
The vectorial equation of the line is represented by:
![\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}](https://tex.z-dn.net/?f=%5Clangle%20x%2C%20y%2C%20z%5Crangle%20%3D%20%5Cvec%20A%20%2B%20t%20%5Ccdot%20%5Coverrightarrow%20%7BAB%7D)
Where
is the parametric variable, dimensionless. Given that
and ![\overrightarrow {AB} = (4,5,6)](https://tex.z-dn.net/?f=%5Coverrightarrow%20%7BAB%7D%20%3D%20%284%2C5%2C6%29)
![\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle](https://tex.z-dn.net/?f=%5Clangle%20x%2Cy%2Cz%20%5Crangle%20%3D%20%5Clangle%20-1%2C-7%2C3%20%5Crangle%20%2B%20t%5Ccdot%20%5Clangle%204%2C5%2C6%20%5Crangle)
Finally, the list of questions are now checked:
1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F
2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F
3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T
4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F
5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F