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Naddika [18.5K]
3 years ago
14

Point a is at (-7,-7) and m is at (-6,-1) what are the coordinates of point b

Mathematics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

The coordinates of point b are (-5,5).

Step-by-step explanation:

Given:

Point a is at (-7,-7) and m is at (-6,-1).

So, to find the coordinates of point b.

Let a (-7,-7) be (x_{1},y_{1}), m (-6,-1) and b (x_{2} ,y_{2}).

Now, putting the formula to get the coordinates:

m=\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2}

⇒(-6,-1)=\frac{-7+x_{2}}{2} , \frac{-7+y_{2}}{2}

So, here we will make two equations to find the value of x_{2} andy_{2}:

-6=\frac{-7+x_{2}}{2}

multiplying both sides by 2

⇒-12=-7+x_{2}

⇒-5=x_{2}

And, now same method for getting the value of y_{2}.

-1=\frac{-7+y_{2}}{2}

multiplying both sides by 2

⇒-2=-7+y_{2}

⇒5=y_{2}.

The value of (x_{2} ,y_{2}) = (-5,5).

Therefore, the coordinates of point b are (-5,5).

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The number of paper clips that crystal has is 42 divided by the number of paper clips that gayle has. If gayle has 11 more paper
Rom4ik [11]

Answer:

• Gayle: 14

• Crystal: 3

Step-by-step explanation:

Let g represent the number of paperclips Gayle has. Then 42/g is the number Crystal has. The relationship between the two numbers is said to be ...

g - (42/g) = 11

Multiplying by g gives ...

g^2 -42 = 11g

g^2 -11g -42 = 0 . . . . subtract 11 g to put into standard form

To factor this, you are looking for two factors of -42 that sum to -11.

-42 = -42·1 = -21·2 = -14·3 = -7·6

You can see that -14 and 3 sum to -11, so the factoring is ...

(g -14)(g +3) = 0

g = 14 . . . . . . . . . . makes the product zero. (The g=-3 solution is extraneous.)

Gayle has 14 paperclips and Crystal has 3.

8 0
3 years ago
Can someone please help me
Gala2k [10]
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8 0
2 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

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Marrrta [24]

Answer:

these lines represent-4+3=-7

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3 years ago
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PIT_PIT [208]
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2y + 3x = 6
2y = -3x + 6
y = (-3/2)x + 3

Keep in mind that the term with the x has to be before the constant, so it can't be y = 3 -(3/2)x

And by the way m is the slope and b is y-intercept, so in <span>y = (-3/2)x + 3, -3/2 is slope and (0,3) is y-intercept</span>
3 0
3 years ago
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