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PIT_PIT [208]
2 years ago
15

Five times the number subtracted from six is triple the number

Mathematics
1 answer:
alexira [117]2 years ago
7 0
6-5x=3x
-5x-3=-6
-8=-6
x=-6/-8
= 3/4 or 0.75
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3x - 5y = -9<br> x + 2y = 8
Rus_ich [418]

Answer: 3x-5y=-9 is simplified to y=3/5x+9/5

x+2y=8 is simplified to y=-1/2x+4

3 0
2 years ago
Read 2 more answers
Plz help I will give anyone who answers this correctly 100 points.
dsp73

Answer:

126.

Step-by-step explanation:

Each rectangle is a step. We'll start with the top one. This is simple: 6 times 3.

6 * 3 = 18.

The farthest left is 5 times 3.

5 * 3 = 15.

The crossed one is 6 times 5.

6 * 5 = 30.

The one to the right of the crossed one is 3 times 5, again.

3 * 5 = 15.

The farthest right is 6 times 5, again.

6 * 5 = 30.

The bottom one is 6 times 3, again.

6 * 3 = 18.

Now, we add.

18 + 18 = 36.\\15 + 15 = 30.\\30 + 30 = 60.\\36 + 30 + 60 = 126.

8 0
3 years ago
HELP IM FAILING MATH I NEED HELP :(
CaHeK987 [17]

Answer:idk

Step-by-step explanation:

idk

7 0
3 years ago
Read 2 more answers
What is the answer to -3+p=?
nata0808 [166]
There is not an answer to an expression. 

-3+p is an expression, unless there was an equal sign and a sum at the end, that is when we can solve for the variable x. 

-3+p simply equals -3+p
7 0
3 years ago
Read 2 more answers
A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write
REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0
2 years ago
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