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nexus9112 [7]
3 years ago
11

Goodmorning I can’t seem to remember this can someone help me

Physics
1 answer:
Bumek [7]3 years ago
6 0

Explanation:

3 cause the triangle method of addition are connected to tips of one vector

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Newtons second law in words??​
Dennis_Churaev [7]

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object

Explanation:

it's newton's second law

5 0
2 years ago
A wheel has a rotational inertia of 16 kgm2. Over an interval of 2.0 s its angular velocity increases from 7.0 rad/s to 9.0 rad/
german

Answer:

<h2>128.61 Watts</h2>

Explanation:

Average power done by the torque is expressed as the ratio of the workdone by the toque to time.

Power = Workdone by torque/time

Workdone by the torque = \tau \theta = I\alpha * \theta

I is the rotational inertia = 16kgm²

\theta = angular\ displacement

\theta = 2 rev = 12.56 rad

\alpha \ is \ the\ angular\ acceleration

To get the angular acceleration, we will use the formula;

\alpha = \frac{\omega_f^2- \omega_i^2}{2\theta}

\alpha = \frac{9.0^2- 7.0^2}{2(12.54)}\\\alpha = 1.28\ rad/s^{2}

Workdone by the torque = 16 * 1.28 * 12.56

Workdone by the torque = 257.23 Joules

Average power done by the torque = Workdone by torque/time

=  257.23/2.0

= 128.61 Watts

8 0
3 years ago
A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electro
pishuonlain [190]

Explanation:

It is given that the number of electrons passing through the cross-sectional area in 1 s is 3.4 \times 10^{18}. Also, we know that charge on an electron is -1.60 \times 10^{-19} C, then negative charge crossing to the left per second is  as follows.

         I- = 3.4 \times 10^{18} electrons \times -1.6 x 10^{-19} C/electrons

         I- = 0.544 A

As it is given that the number of protons crossing per second is 1.4 \times 10^{18}, as the charge on the proton is +1.60 \times 10^{-19} C, then positive charge crossing to the right per second is calculated as follows.

          I+ = 1.4 \times 10^{18} electrons \times 1.6 \times 10^{-19} electrons/C

            I+ = 0.224 A

          I = l I+ l + l I- l

So,    I = 0.544 + 0.224

            = 0.768 A

Thus, we can conclude that the current in given hydrogen discharge tube is 0.768 A.

8 0
3 years ago
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.320 m2. at
AlexFokin [52]
Remember, half of the energy in an EM wave is in the E field, the rest is in the B field. Thus, multiply E field energy by 2.
To calculate the energy of the wave you must then use the following equation: W = A*t*c*2*(1/2*E^2*Eo). Where, A = Area, t = time, c = speed of light (which is a constant), E = Electric field, E0 = vacuum permittivity (8.85*10^-12 Nm^2/C^2). Substituting W =(0.320)*(26)*(3*10^8)*(2)*((1/2)*(1.95*10^-2)^2*(8.854*10^-12)) = 8.40*10^-6 J
5 0
3 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
den301095 [7]

Answer:

F = 5.256 x 10^{3} N

Explanation:

From the work energy theorem we know that:

The net work done on a particle equals the change in the particles kinetic energy:

W = F.d, ΔK =\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}  , F.d = \frac{1}{2}mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}

where:

W = work done by the force

F = Force

d = Distance travelled

m = Mass of the car

vf, vi = final and initial velocity of the car

kf, ki = final and initial kinetic energy of the car

Given the parameters;

m = 830kg

vi = 1.9 m/s

vf = 0 km/h

d = 0.285 m

Inserting the information we have:

F.d = \frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}

F = \frac{\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i} }{d}

F = \frac{ 0   - \frac{1}{2}  X830 X 1.9^{2} }{0.285}

F = 5.256 x 10^{3} N

3 0
3 years ago
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