Answer:
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object
Explanation:
it's newton's second law
Answer:
<h2>
128.61 Watts</h2>
Explanation:
Average power done by the torque is expressed as the ratio of the workdone by the toque to time.
Power = Workdone by torque/time
Workdone by the torque =
= 
I is the rotational inertia = 16kgm²



To get the angular acceleration, we will use the formula;


Workdone by the torque = 16 * 1.28 * 12.56
Workdone by the torque = 257.23 Joules
Average power done by the torque = Workdone by torque/time
= 257.23/2.0
= 128.61 Watts
Explanation:
It is given that the number of electrons passing through the cross-sectional area in 1 s is
. Also, we know that charge on an electron is
, then negative charge crossing to the left per second is as follows.
I- =
I- = 0.544 A
As it is given that the number of protons crossing per second is
, as the charge on the proton is
, then positive charge crossing to the right per second is calculated as follows.
I+ =
I+ = 0.224 A
I = l I+ l + l I- l
So, I = 0.544 + 0.224
= 0.768 A
Thus, we can conclude that the current in given hydrogen discharge tube is 0.768 A.
Remember, half of the energy in an EM wave is in the E field, the rest is in the B field.
Thus, multiply E field energy by 2.
To calculate the energy of the wave you must then use the following equation: W = A*t*c*2*(1/2*E^2*Eo). Where, A = Area, t = time, c = speed of light (which is a constant), E = Electric field, E0 = vacuum permittivity (8.85*10^-12 Nm^2/C^2). Substituting W =(0.320)*(26)*(3*10^8)*(2)*((1/2)*(1.95*10^-2)^2*(8.854*10^-12)) = 8.40*10^-6 J
Answer:
F = 5.256 x 
Explanation:
From the work energy theorem we know that:
The net work done on a particle equals the change in the particles kinetic energy:
W = F.d, ΔK =
where:
W = work done by the force
F = Force
d = Distance travelled
m = Mass of the car
vf, vi = final and initial velocity of the car
kf, ki = final and initial kinetic energy of the car
Given the parameters;
m = 830kg
vi = 1.9 m/s
vf = 0 km/h
d = 0.285 m
Inserting the information we have:
F.d = 
F = 
F = 
F = 5.256 x 