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Bogdan [553]
3 years ago
9

A football quarterback runs 15.0 m straight down the playing field in 2.30 s. He is then hit and pushed 3.00 m straight backward

in 1.74 s. He breaks the tackle and runs straight forward another 28.0 m in 5.20 s.
Calculate his average velocity (in m/s) for each of the three intervals. (Assume the quarterback's initial direction is positive. Indicate the direction with the sign of your answer.)
Physics
1 answer:
Monica [59]3 years ago
7 0

Answer:

6.52 m/s

1.72 m/s

5.38 m/s

Explanation:

this question requires us to find the average velocity.

1. velocity in straight down direction:

velocity = distance/time

= 15.0/2.30

= 6.52 m/s

2. velocity in straight backward direction:

velocity = distance/time

= 3.00 /1.74

= 1.72m/s

3. velocity in straight forward direction

velocity = distance/time

= 28.0/5.20

= 5.38 m/s

these are the his velocities for each if the intervals.

thank you!

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