Answer:
the answer to the question is calcium
Q: A rock is thrown off of a 100 foot cliff with an upward velocity of 45 m/s. As a result its height after t seconds is given by the formula:
h(t)=100+45t−4.9t2
(a)
What is its height after 3 seconds?
(b)What is its velocity after 3 seconds?
Answer:
(a) 190.9 m.
(b) 15.6 m/s upward
Explanation:
Given:
h(t) = 100 + 45t - 4.9t²
The height after 3 seconds,
t = 3 s
Substitute the value of t in to the equation above.
h(3) = 100+45(3)-4.9(3)²
h(3) = 100+135-44.1
h(3) = 190.9 m
Therefore the height after 3 seconds = 190.9 m.
(b) Velocity after 3 seconds
The velocity is obtained by differentiating h(t) with respect to time
v = dh(t)/dt
dh(t)/dt = 45-9.8t
v = 45 - 9.8t ......................................... Equation 1
t = 3 s.
Substitute the value of t into the equation above,
v = 45 - 9.8(3)
v = 45- 29.4
v = 15.6 m/s
Thus the velocity after 3 seconds = 15.6 m/s upward
Answer:
The mass of the beam is 0.074 kg
Explanation:
Given;
length of the uniform bar, = 1m = 100 cm
Set up this system with the given mass and support;
0-----------------33cm-----------------------------------100cm
↓ Δ ↓
0.15kg m
Where;
m is mass of the uniform bar
Apply the principle of moment to determine the value of "m"
sum of anticlockwise moment = sum of clockwise moment
0.15kg(33 - 0) = m(100 - 33)
0.15(33) = m(67)
Therefore, the mass of the beam is 0.074 kg
Answer:
The man fires an 80 g arrow so that it is moving at 80 m/s when it hits and embeds in a 8.0 kg block resting on ice. how far will the block slide on the ice before stopping? a 7.1 n friction force opposes its motion.
Explanation: