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fiasKO [112]
3 years ago
12

A mass of 400 g is hanging from a spring with a spring constant of 10 N/m. The mass is pulled down a distance of 10 cm from its

equilibrium position and released. How long does it take to reach the equilibrium position again

Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Explanation:

Below is an attachment containing the solution.

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Gravitational force on the moon is only 1/6 that of the gravitational force on earth. what would be the weight of a 10-kg object
MA_775_DIABLO [31]
According to Newton's Second Law of Motion, the force is equal to the mass of an object multiplied by its acceleration. When you talk about gravitational force, the acceleration referred to here is the acceleration due to gravity. This is very familiar to us in physics. The acceleration due to gravity on Earth is equal to 9.81 m/s². It actually depends on the location. According to the Universal Law of Gravitation:

F = Gm₁m₂/d²

The force is a factor of the product of two masses and their distance from each other. The G is a constant called the universal gravitational constants. So, gravitational force is actually a relative force exerted by one body to another. 

Going back the Second Law of Motion, we can modify the equation to:

F = mg

Since it is mentioned that the gravity on the moon is only 1/6 of the Earth, then the gravity for moon is:
g,moon = 1/6(9.81) = 1.635 m/s²
So, let's compare the weight of the object with a mass of 10 kg. The weight is actually the force due to gravity pulling you towards the center of the body.

Weight on Earth = (10 kg)(9.81 m/s²) = 98.1 N
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The mass, on the other hand, is not affected by gravity. It is always constant. Therefore, the mass of the object on the moon is the same with its mass on the Earth.
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3 years ago
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