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Vlada [557]
3 years ago
12

Which mineral identification property deals with the way light reflects off a mineral?

Chemistry
2 answers:
Ronch [10]3 years ago
7 0
Luster deals with the way light reflects off a mineral
slavikrds [6]3 years ago
6 0
Luster describes how a mineral<span> appears to </span>reflects light<span>, and how brilliant or dull ... Metallic - </span>Minerals<span>with a metallic luster are opaque and reflective, like metal. ... a </span>mineral property<span>, and is not commonly usually used to help </span>identify<span> a </span>mineral<span>.</span>
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In which substance does sulfur have a negative oxidation number?<br>Na2S<br>CaSO4<br>S<br>SO2
leonid [27]

Answer:

Na2S  

Explanation:

Na2S: Na (always +1). S (-2) in this formula

CaSO4:   Ca (always +2). O (-2). => S (+6) in CaSO4

S (0)

SO2:  O(-2) => S (+4)

Hope this answer will help you! Have a nice day!

3 0
3 years ago
The spectral lines energetic object known as quasars
docker41 [41]

Answer:

Quasars inhabit the centers of active galaxies and are among the most luminous, powerful, and energetic objects known in the universe, emitting up to a thousand times the energy output of the Milky Way, which contains 200–400 billion stars.

Explanation:

sorry if im wrong

6 0
3 years ago
Pls help 2-3 tyvm ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎
Triss [41]

Answer:

I could I guess?

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Explanation:

6 0
3 years ago
If the half-life of 37Rb is 4.7x101 years, how long would it take for 0.5 grams of a 2 gram sample to radioactively decay?
k0ka [10]

<u>Answer:</u> The time required will be 19.18 years

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

We are given:

t_{1/2}=4.7\times 10^1yrs

Putting values in above equation, we get:

k=\frac{0.693}{4.7\times 10^1yr}=0.015yr^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant  = 0.015yr^{-1}

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 2 g

[A] = amount left after decay process =  (2 - 0.5) = 1.5 g

Putting values in above equation, we get:

0.015yr^{-1}=\frac{2.303}{t}\log\frac{2}{1.5}\\\\t=19.18yrs

Hence, the time required will be 19.18 years

4 0
3 years ago
What is the correct name for this formula: BaCl2
Inessa05 [86]
BaCI2 stands for Barium Chloride. Hope this helps!
3 0
3 years ago
Read 2 more answers
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