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3 years ago

PLEASE HELP Prove that: 2^13–2^10–2^9 is divisible by 13

Mathematics

1 answer:

insens350 [35]3 years ago

8 0

Answer:

See below.

Step-by-step ,explanation:

2^13 – 2^10 – 2^9

Take out the GCF, 2^9 :

= 2^9 (2^4 - 2 - 1)

= 2^9(16 - 3)

= 13 * 2^9.

So it must be divisible by 13.

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Prime factorization of 60 100 85 Explain in steps

gayaneshka [121]

Answer:

60=2×2×3×5
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2 years ago

what information is necessary to prove the triangles congruent by ASA? by AAS ? show your work please.

Zielflug [23.3K]

Answer:

See Explanation

Step-by-step explanation:

For ASA

$\angle R \cong \angle E$

$RQ \cong EF$

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$\angle P \cong \angle G$

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2 years ago

Please help! Thank you if you do :)

Kruka [31]

Step-by-step explanation:

A(-5,1) and B(0,4)

$m \: = \: \frac{y2 - y1}{x2 - x1}$

X1=0 , Y1=4 X2= -5 , Y2=1

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C is the answer

6 0

2 years ago

Solve the following system. Please show me how you did it.

Andrej [43]

Answer:

x = 3, y = 4 and z = -5.

Step-by-step explanation:

Use the elimination method:

-3x + 2y + z = -6...........(1)

x + 3y + 2z = 5..............(2)

4x + 4y + 3z = 13..........(3)

Multiply the first equation by -2:

6x - 4y - 2z = 12 Add this to equation (2):

7x - y = 17...........(4)

Now Multiply equation (2) by 3 and equation (3) by -2

3x + 9y + 6z = 15 ............(5)

-8x - 8y - 6z = -26............(6) Adding (5) + (6):

-5x + y = -11..........(7)

Now Add (7) and (4):

2x = 6

x = 3.

Now substitute for x in (4):

7(3) - y = 17

-y = 17 - 21 = -4

y = 4.

Finally substitute for x and y in equation (3) to find z:

4(3) + 4(4) +3z = 13

3z = 13 - 12 - 16 = -15

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4 0

2 years ago

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malfutka [58]

Answer:

35
x 100
00
500

Step-by-step explanation:

35 divided by 7 is 5. 3,500 is 35 x 100. 35 hundreds (3,500) divided by 7 is 5 hundred (5 with 00 at the end). 3,500 divided by 7 is 500.

Hope it helps!

7 0

2 years ago