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Serhud [2]
3 years ago
7

PLEASE HELP Prove that: 2^13–2^10–2^9 is divisible by 13

Mathematics
1 answer:
insens350 [35]3 years ago
8 0

Answer:

See below.

Step-by-step ,explanation:

2^13 – 2^10 – 2^9

Take out the GCF,  2^9 :

= 2^9 (2^4 - 2 - 1)

= 2^9(16 - 3)

= 13 * 2^9.

So it must be divisible by 13.

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12x + 8 + 84 = 15х +9
RideAnS [48]

Answer:

x = 83/3.

Step-by-step explanation:

12x + 8 + 84 = 15х +9

Solving for x:

8 + 84 - 9 = 15x - 12x

83 = 3x

x = 83/3.

3 0
3 years ago
Read 2 more answers
I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an
Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

\mu = 0 - 5 = -5

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - (-5)}{\sqrt{13}}

Z = \frac{6}{\sqrt{13}}

Z = 1.66

Z = 1.66 has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0
2 years ago
I need the answer fast please
shusha [124]
The diameter of the circle is needed. But to solve, you would simply multiply the diameter of the circle by pi (3.14).
3 0
2 years ago
What is the equivalent to log 1/2 462 ?
Ulleksa [173]

Answer:

Exact Form: log1/2(462)

Decimal Form:

8.85174904

Step-by-step explanation:

6 0
3 years ago
Tre Algebra<br>Assignment Day 4<br>Solve each equation<br>1) -2-4-2<br>-2<br>.1​
Debora [2.8K]

Answer:

If your question is -2 - 4 - 2 - 2.1 then the answer is -10.1

Step-by-step explanation:

-2 - 4 - 2 - 2.1

= (-2 - 4 ) - 2 - 2.1                Combine -2 with -4 or subtract them

=  -6 - 2 - 2.1                        

= (-6 - 2 )- 2.1                       Combine -6 and -2

= -8 -2.1                                Combine -8 and -2.1

= -10.1

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : ) </em></u></h3><h3><u><em>And always, </em></u></h3><h3><u><em>SIMPLIFY BANANAS          : )</em></u></h3>
4 0
3 years ago
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