Given:
The height h of an object after t seconds is

The height of a neighboring 50-foot tall building is modeled by the equation h=50.
The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.
To find:
The statement which describes the validity of these solutions.
Solution:
We have,

Here, t is the time in seconds.
For t=-2,



For t=5,



So, the value of h is 50 at t=-2 and t=5.
We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.
The solution t = 5 is the only valid solution to this system since time cannot be negative.
Therefore, the correct option is C.
Answer:
0.105
Step-by-step explanation:
0.25/100 x 42 = 0.105
Answer:
(a) (2w)w 2. (b) 3p. 3 × 4p ... y = –5, and z = 3, ... x = 7, and x t = 2, t. (d) (kx + 2 kx y. + 2 )y z when k = 3.5, k x = 4, x y = –5, and z = 3,. (e)
Step-by-step explanation: hey sorry if its wronge but i tryied :P
T-T
Answer:
A(n) = 5.1×n + 4.5
Step-by-step explanation:
A(n) = A(n-1) + 5.1
A(1) = 9.6
A(n) - A(n-1) = 5.1 ,where n ≥ 1
This means that (A(n)) is an arithmetic sequence where :
<u>The common difference</u> r = 5.1
and
<u>The first term</u> A(1) = 9.6
Therefore
A(n) = A(1) + (n - 1)×r
= 9.6 + (n - 1)×5.1
= 9.6 + 5.1×n - 5.1
= 5.1×n + (9.6 - 5.1)
= 5.1×n + 4.5