Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
In which:
is the sample mean.
is the standard deviation for the population.
The margin of error is given by:
In this problem, we have that the parameters are given as follows:
.
Hence, solving for n, we find the sample size.
Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
745.44 square mm
Step-by-step explanation:
The figure can be decomposed into ...
- a semicircle of radius 12.5 mm
- a rectangle 12.5 mm by 25 mm
- a triangle 12.5 mm by 30 mm
The relevant area formulas are ...
Semicircle: A = 1/2πr² = 1/2π(12.5 mm)² ≈ 245.437 mm²
Rectangle: A = LW = (12.5 mm)(25 mm) = 312.500 mm²
Triangle: A = 1/2bh = 1/2(12.5 mm)(30 mm) = 187.500 mm²
Total area of the figure is ...
245.437 +312.500 +187.500 = 745.437 . . . mm²
The area of the figure is about 745.44 square mm.
Answer:
735x0.01
Step-by-step explanation:
Answer:
382.19cm²
Step-by-step explanation:
a / sin(A) = b / sin(B)
a / sin(68) = 53 / sin(95)
a = (53 x sin(68)) / sin(95)
a = 49.33
area = ½absin(C)
C = 180 - (95 + 68)
C = 180 - 163
C = 17°
area = ½(53)(49.33)sin(17)
area = 382.19cm²
Answer:
We have, from distance formula.
AB² = (5-0)² + (2-6)² = 5² + 4² = 25 + 16 = 41
BC² = (0+5)² + (6+7)² = 5² + 13² = 25 + 169 =194
AC² = (5+5)² + (2+7)² = 10² + 9² = 100+81 = 181
Here, BC² ≠ AB² + AC².
So, the triangle is not a right triangle
