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Oliga [24]
3 years ago
8

Chapter 15 of your textbook discusses conjugation and various reactions of 1,3-dienes. In CHE 321, we discussed various ways to

make alkenes, but we did not discuss methodology for making dienes. Fortunately, we can apply some of our standard CHE 321 reactions to this important problem. Choose the major product (compound A) of the following reaction sequence.
Chemistry
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

Dienes are alkenes that contain two carbon-carbon double bonds, so they have the same properties as these hydrocarbons.

In the attached file are the two reactions of dienes production.

Explanation:

Two ways to obtain dienes are as follows:

-Reaction of oxidative dehydrogenation of an alkane, is an exothermic process and occurs at lower temperatures, diene and water are formed, generating greater conversion at lower temperature levels.

-Dehydration of primary alcohols. The treatment of alcohols with acid at elevated temperatures produces dienes due to water loss. For example, heating ethanol in the presence of sulfuric acid produces ethene by the loss of a water molecule.

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The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca
defon
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
4 0
3 years ago
Read 2 more answers
What state of matter has the most kinetic energy
kvv77 [185]

Answer: Gas

Explanation:

since the gas molecules arent being forcefully bonded together like a solid would be, and liquids tend to have lower kinetic energy than solids

3 0
3 years ago
What are the base units the SI units are based on?<br> A-10<br> B-100<br> C-1,000<br> D-1
Olegator [25]

Answer:

A-10

Explanation:

In the SI, designations of multiples and subdivision of any unit may be arrived at by combining with the name of the unit the prefixes deka, hecto, and kilo meaning, respectively, 10, 100, and 1000, and deci, centi, and milli, meaning, respectively, one-tenth, one-hundredth, and one-thousandth.

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4 0
2 years ago
Suppose Highlinium-308 can also undergo positron emission
____ [38]

Answer:

The atomic number of burienium will be 307.

Explanation:

During positron emission proton is converted into the neutron and one electron neutrino with positron is released. It means the atomic number will be reduce by one and atomic mass remain same.

For example:

²³Mg₁₂    →     ₁₁Na²³+ e⁺+ Ve

Similarly, when highlinium-308 undergoes positron emission the new element burienium is produced and the atomic number will be 307 while atomic mass remain same.

Properties of beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

4 0
3 years ago
If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te
attashe74 [19]
Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
pV=nRT
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}

If the supported load is W kg, then
p_{1} =  \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} =  20.3718W \, Pa
Similarly,
p_{2} =  \frac{4W}{\pi d_{2}^{2}} \, Pa

\frac{p_{1}}{p_{2}} =  \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}

Because p₁/p₂ = T₁/T₂, therefore
16d_{2}^{2} =  \frac{293}{423}  \\\\ d_{2}^{2} =  \frac{0.6927}{16}  \\\\ d_{2} = 0.2081 \, m

The minimum piston diameter at 150 C is 20.8 cm.

Answer: 20.8 cm diameter

8 0
3 years ago
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