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Tresset [83]
2 years ago
15

How many moles of KOH are there in 27.5 mL of 0.250 M KOH?

Chemistry
1 answer:
zaharov [31]2 years ago
7 0

Answer:

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

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What is the pH of a solution made by mixing 200 mL of 0.025M HCl and 150 mL of 0.050 M HCl?
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Answer:

The answer to your question is pH = 1.45  

Explanation:

Data

pH = ?

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Process

1.- Calculate the number of moles of each solution

Solution 1

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result

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Solution 2

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-result

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2.- Sum up the number of moles

Total moles = 0.005 + 0.0075

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3.- Sum up the volume

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4.- Calculate the final concentration

Molarity = 0.0125 / 0.35

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5.- Calculate the pH

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-Substitution

pH = -log[0.0357]

-Result

pH = 1.45    

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