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Vlada [557]
3 years ago
11

Write the net ionic equation:. . A solution of diamminesilver(I) chloride is treated with dilute nitric acid

Chemistry
2 answers:
malfutka [58]3 years ago
6 0

<u>Answer:</u> The net ionic equation is given below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of diamminesilver(I) chloride and dilute nitric acid is given as:

[Ag(NH_3)_2]Cl(aq.)+2HNO_3(aq.)\rightarrow AgCl(s)+NH_4NO_3(aq.)

Ionic form of the above equation follows:

[Ag(NH_3)_2]^+(aq.)+Cl^-(aq.)2H^+(aq.)+2NO_3^-(aq.)\rightarrow AgCl(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

[Ag(NH_3)_2]^+(aq.)+Cl^-(aq.)2H^+(aq.)\rightarrow AgCl(s)+2NH_4^+(aq.)

Hence, the net ionic equation is written above.

zimovet [89]3 years ago
5 0
<span> Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl </span>
<span>or
 Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl  this the complete balanced equation
now remove spectator ions to get net ionic equation
so 
</span>
<span> 2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3-  2NO3-  2H+  [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
</span>hope it helps
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Calculate the number of atoms in a 5.31 x 10³ g sample of sodium.<br><br> number of atoms:
Leviafan [203]

Answer:

        no of atoms =   13.9 x 10^25

Explanation:

                No. of moles = mass of compound / molar mass of   compound

   

       As ; mass of sodium = 5.3 x 10^3 g

       

        Molar mass of sodium = 22.9 g/ mol

         

        putting values  

         

         n = 5.3 x 10^3 / 22.9

       

         n = 231.4 mol

Also; no of mol (n) = no of particles / Avagadros number

               so no of particles = n x Avagadros no.

     

               put n = 231.4 and Avagadros no = 6.023 x 10^23

 

                 no of particles = 231.4 x 6.023 x 10^23

                                   =   13.9 x 10^25  

       

             

4 0
2 years ago
147 J is what kind of quantity
ioda

Answer:

quantitative data

Explanation:

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3 0
4 years ago
A jet airplane has a velocity of 1145 knots. A knot is 1 nautical mile (nm)/hr. A nautical
ra1l [238]

Answer:

589.038 m/s

Explanation:

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4 0
2 years ago
This sketch of a neutral molecule is shaded red or blue wherever the electrostatic potential at the molecule's surface isn't zer
Natalka [10]

The electrostatic potential is the work done to remove the charge. The molecule showing the potential map shows that it is HI.

<h3>What is electronegativity?</h3>

Electronegativity is the elemental property to attract the electron toward the atom and is affected by atomic number and the atomic radius. The map shows that the molecule is made of two different atoms and has linear geometry.

Due to the linear geometry, the molecule cannot be Br₂ and SO₃ as they are nonpolar and nonlinear respectively. Similarly, BrF and ICl can be eliminated as they are interhalogen compounds. In the HI molecule, the hydrogen atom is a cation and the iodine atom is an anion that has high electronegativity differences.

Therefore, HI is the molecule depicted in the potential map.

Learn more about the electrostatic potential here:

brainly.com/question/14889552

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8 0
3 years ago
A sample of wood from the remains of a ship was found to contain 40.0% of C-14 as of ordinary wood found now. If the half-life p
kondaur [170]

Answer:

7628 y

Explanation:

Carbon-14 is radioactive and it follows the first-order kinetics for a radioactive decay. The first-order kinetics may be described by the following integrated rate law:

ln(\frac{[A]_t}{[A]_o})=-kt

Here:

[A]_t is the mass, moles, molarity or percentage of the material left at some time of interest t;

[A]_o is the mass, moles, molarity or percentage of the material initially, we know that initially we expect to have 100 % of carbon-14 before it starts to decay;

k = \frac{ln(2)}{T_{\frac{1}{2}}} is the rate constant;

t is time.

The equation becomes:

ln(\frac{[A]_t}{[A]_o})=-\frac{ln(2)}{T_{\frac{1}{2}}}t

Given:

\frac{[A]_t}{[A]_o} = \frac{40.0 %}{100.0 %}

T_{\frac{1}{2}} = 5770 y

Solve for time:

t = -\frac{ln(\frac{[A]_t}{[A]_o})\cdot T_{\frac{1}{2}}}{ln(2)}

In this case:

t = -\frac{ln(\frac{40.0\%}{100.0\%})\cdot 5770 y}{ln(2)}

t = 7628 y

3 0
4 years ago
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