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Degger [83]
3 years ago
15

Help please only answer if you know question below

Mathematics
1 answer:
AlekseyPX3 years ago
3 0
The answer is x=-16
2/3x-1/6x=-8 (combine like terms)
3/6x=-8
1/2x=-8
x=-16

Hope this helps
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A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?
stealth61 [152]
A school custodian waxed a gymnasium floor that measured 20 feet by 20 feet. How many square feet did she have to wax?

If it's 20 feet * 20 feet = to
400 sq.ft

Hope this helps!
6 0
3 years ago
A fish swims at 10 ft below sea level , and then swims another 10 ft deeper to avoid a shark. Write an addition expression that
sergij07 [2.7K]

Answer:

0+(-10+-10) i don't know if this is what you need..sry if it's not

Step-by-step explanation:

3 0
3 years ago
An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up. The
Nikolay [14]

The length of the ladder nearest hundredth of a foot is 23 feet.

We have given that,

An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 20 feet up.

The ladder makes an angle of 77^{\circ}  the ground.

<h3>What is the sin ratio?</h3>

sin(\theta)=\frac{perpendicular \ side}{hypotenous}

Therefore we get,

\implies\frac{22}{H} =sin(77)

\implies H=22/sin(77)

\implies 22.59ft\\\\=23ft

Therefore, The length of the ladder nearest hundredth of a foot is 23 feet.

To learn more about the trigonometric ratio visit:

brainly.com/question/24349828

#SPJ1

7 0
2 years ago
Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/
nirvana33 [79]
2 2/3 + 2 3/4 is equal to 5 5/12 so the drapes will be 5 5/12 feet long (or 5 feet 5 inches)
3 0
3 years ago
Read 2 more answers
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
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