Answer:
Work done, W = 337.35 Joules
Explanation:
It is given that,
Mass of the crate, m = 21 kg
Force exerted by the worker on the crate, F = 224.9 N
The crate is inclined at an angle of 40 degrees.
Distance covered by the slide, d = 1.5 m
Let W is the work is done on the crate by the worker's applied force. it is equal to the product of force and distance. It is given by :

W = 337.35 Joules
So, the work is done on the crate by the worker's applied force is 337.35 Joules. Hence, this is the required solution.
Answer:
6.45
Explanation:
Equation: E= Q/A(8.85*10^-12)
A= Q/E / (8.85*10^-12)
A= (4.98*10^-7)/8720 / (8.85*10^-12)
A=6.45
Got it right on acellus
Big truzz
Black surfaces is you'r answer. or dark mater. ya those are you'r answer.