Answer:
<em><u>When</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>travels</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>straight</u></em><em><u> </u></em><em><u>line</u></em><em><u>,</u></em><em><u> </u></em><em><u>it's</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>becomes</u></em><em><u> </u></em><em><u>equal</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>displacement</u></em><em><u>.</u></em><em><u> </u></em>
Explanation:
<em><u>Distance</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>actual</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>covered</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>displacement</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>shortest</u></em><em><u> </u></em><em><u>path</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>distance</u></em><em><u> </u></em><em><u>covered</u></em><em><u>.</u></em>
<em><u></u></em>
<em><u>✌</u></em><em><u>Follow</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>❤</u></em>
<em><u>and</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>my</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u> </u></em><em><u>☺</u></em>
Beta decay any of the processes of radioactive disintegration by which some unstable atomic nuclei spontaneously dissipate access energy and undergo a change of one unit of positive charge without any change in mass number the three processes are electron omission positron positron electron a mission and electron capture
The center of mass of the three-mass system is 0.433m.
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. In a collection of unconnected items, the center of mass can also be established.
<h3>
Given:</h3>
Mass of the object, m₁ = 1.03kg
Mass of the object, m₂= 1.50kg
Mass of the object, m₃= 1.10
Taking the location of m as the origin and towards right as positive X-axis.
x₁=0
x₂=0.50m
x₃=0.25+0.50 = 0.75m
The X-coordinate of the center of mass of a system of three masses m₁, m₂ and m₃ located at the positions x₁, x₂ and x₃ on X-axis is given by,
Therefore, the center of mass of the three-mass system is 0.433m.
Learn more about center of mass here:
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The speed of the wave with the given frequency and wavelength is 1.2m/s.
Given the data in the question;
- Wavelength of the wave;
- Frequency;
- Speed of the wave;
<h3>
Wavelength</h3>
Wavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
Where v is velocity/speed and f is frequency.
Now, we can easily get the speed of the wave by substituting our given values into the expression above.
Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701
Answer:
Explanation:
a ) Time period T = 2 s
Angular velocity ω = 2π / T
= 2π / 2 = 3.14 rad /s
Initial moment of inertia I₁ = 200 + mr²
= 200 + 25 x 2.5²
=356.25
Final moment of inertia
I₂ = 200 + 25 X 1.5 X 1.5
= 256.25
b ) We apply law of conservation of momentum
I₁ X ω₁ = I₂ X ω₂
ω₂ = I₁ X ω₁ / I₂
Putting the values
ω₂ = 4.365 rad s⁻¹
c ) Increase in rotational kinetic energy
=1/2 I₂ X ω₂² - 1/2 I₁ X ω₁²
.5 X 256.25 X 4.365² - .5 X 356.25 X 3.14²
= 684.95 J
This energy comes from work done against the centripetal pseudo -force.