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enyata [817]
3 years ago
8

A movie stunt double is supposed to run across the top of a train (in the opposite direction that the train is moving) and just

barely jump off before reaching a tunnel, but after running the entire length of the train (starting from the front). If the train is moving at 50 km/hr, is 3 km long and the tunnel is 40 km away from the end (where the stunt double is going to jump from), how fast (in km/hr) will the stunt double need to run
Physics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

3.49km/hr

Explanation:

This train is moving at 50km/hr

Distance = length of train + distance of tunnel

= 3 km + 40 km

= 43 km

Time taken by train to get to tunnel

Time = distance / velocity

Time = 43 km/50km perhour

= 0.86

How fast will stunt double have to run?

Velocity = 3km/0.86

= 3.49 km/hr

The stunt double will have to run as fast as 3.49 kilometer per hour

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Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial (v_{o}) and final speeds (v_{f}), measured in meters per second, and acceleration (a), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom (t), measured in seconds, is:

t = \frac{v_{f}-v_{o}}{a} (1)

If we know that v_{o} = 0\,\frac{m}{s}, v_{f} = 17.5\,\frac{m}{s} and a = 2.94\,\frac{m}{s^{2}}, then the time taken is:

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t = 5.952\,s

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our 3.80-kg physics book is placed next to you on the horizontal seat of your car. The coefficient of static friction between th
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Answer:

Explanation:

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