You are correct because nothing is being done to the cake
        
                    
             
        
        
        
1) 
The capacitance of a parallel-plate capacitor is given by:

where
 is the vacuum permittivity
 is the vacuum permittivity
A is the area of each plate
d is the distance between the plates
Here, the radius of each plate is

so the area is

While the separation between the plates is

So the capacitance is

And now we can find the energy stored,which is given by:

2) 0.71 J/m^3
The magnitude of the electric field is given by

and the energy density of the electric field is given by

and using 
 , we find
, we find

 
        
             
        
        
        
Answer:
 
50 W
Explanation:
<h3>
<u>Given :</u></h3>
- Force applied = 100 N
- Distance covered = 5 metres
- Time = 10 seconds
<h3>
<u>To find :</u></h3>
 
 Power
<h3>
<u>Solution :</u></h3>
For calculating power, we first need to know about the work done.

Now, substituting values in the above formula;
 
Work = 100 × 5 
 = 500 Nm or 500 J
We know that, 

Substituting values in above formula;
Power = 500/ 10
 = 50 Nm/s or 50 W
Hence, power = 50 W .
 
 
        
             
        
        
        
Answer:
<h3>The answer is 40 N</h3>
Explanation:
The force acting on an object can be found by using the formula
<h3>force = mass × acceleration</h3>
From the question
mass = 4 kg
acceleration = 10 m/s²
So we have
force = 4 × 10
We have the final answer as
<h3>40 N</h3>
Hope this helps you
 
        
             
        
        
        
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,


Therefore the friction force at 29Km / h would be,




In this way the tension exerts between first car and locomotive is,



Therefore the tension in the coupling between the car and the locomotive is 