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2 answers:
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1)
The capacitance of a parallel-plate capacitor is given by:
where
is the vacuum permittivity
A is the area of each plate
d is the distance between the plates
Here, the radius of each plate is
so the area is
While the separation between the plates is
So the capacitance is
And now we can find the energy stored,which is given by:
2) 0.71 J/m^3
The magnitude of the electric field is given by
and the energy density of the electric field is given by
and using
, we find
Answer:
50 W
Explanation:
<h3><u>Given :</u></h3>- Force applied = 100 N
- Distance covered = 5 metres
- Time = 10 seconds
Power
<h3><u>Solution :</u></h3>For calculating power, we first need to know about the work done.
Now, substituting values in the above formula;
Work = 100 × 5
= 500 Nm or 500 J
We know that,
Substituting values in above formula;
Power = 500/ 10
= 50 Nm/s or 50 W
Hence, power = 50 W .
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,
Therefore the friction force at 29Km / h would be,
In this way the tension exerts between first car and locomotive is,
Therefore the tension in the coupling between the car and the locomotive is