W1=200rpm*2pi/60=20.9rad/s
w2=200rpm-.10(200rpm)=180rpm
180rpm*2pi/60=18.8rad/s
a=(18.8-20.9)/10= -.21rad/s^2
I=1/2(28)(.15)^2
I=.315kg*m^2
Torque= -.21(.315)=.06615 N*m
Friction force= -.06615/.15=-.441 N
Normal force of man=.441/.2= 2.205 N
Final answer: -2.205 N
Answer:
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The calculated total mechanical energy will reduce if the oscillation is not perpendicular to the photogate.
<h3>Mechanical energy at the lowest position of the pendulum</h3>
The mechanical energy at the lowest position of the pendulum is calculated as follows;
<h3>When the direction of the motion changes</h3>
let the velocity of the pendulum = vsin(θ)
when the velocity is perpendicular = vsin(90) = v
At any direction different from perpendicular direction, the mechanical energy reduces by;
Thus, the calculated total mechanical energy will reduce if the oscillation is not perpendicular to the photogate.
Learn more about mechanical energy here: brainly.com/question/24443465
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