Ask question

Ask question

All categories

denis-greek [22]

3 years ago

11

Draw the intermediate (in the first box) that forms in the reaction of 1-methylcyclopentene with br2 in ccl4, then draw the expe

cted product (in the second box). do not provide stereochemistry. interactive 3d display mode

1 answer:

svetlana [45]3 years ago

7 0

Answer:

The product of the reaction is 1,2 di-bromo-1-methylcyclopentane.

Explanation:

You might be interested in

PLZ HELP *NO LINKS*

Radda [10]

Answer: (1). There are 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP.

(2). The density of gaseous arsine is 3.45 g/L.

Explanation:

1). At STP the pressure is 1 atm and temperature is 273.15 K. So, using the ideal gas equation number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\1 atm \times 0.372 L = n \times 0.0821 L atm/mol K \times 273.15 K\\n = 0.0165 mol$

2). As number of moles are also equal to mass of a substance divided by its molar mass.

So, number of moles of Arsine $(AsH_{3})$ (molar mass = 77.95 g/mol) is as follows.

$No. of moles = \frac{mass}{molar mass}\\0.0165 mol = \frac{mass}{77.95 g/mol}\\mass = 1.286 g$

Density is the mass of substance divided by its volume. Hence, density of arsine is calculated as follows.

$Density = \frac{mass}{volume}\\= \frac{1.286 g}{0.372 L}\\= 3.45 g/L$

Thus, we can conclude that 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP and the density of gaseous arsine is 3.45 g/L.

4 0

3 years ago

The formula equation of Sodium carbonate + hydrochloric acid

dusya [7]

Answer:

the reaction is: Na2CO3 + 2HCl ===》 2NaCl + H2O + CO2(g)

6 0

3 years ago

A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The mol

KonstantinChe [14]

Answer:

Empirical formula is CH₂O.

Molecular formula = C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 3.36 g

Mass of carbon = 20.00 g

Mass of oxygen = 26.64 g

Molar mass of compound = 180.156 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Number of gram atoms of H = 3.36 / 1.01 = 3.3

Number of gram atoms of O = 26.64 / 16 = 1.7

Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

C : H : O

1.7/1.7 : 3.3/1.7 : 1.7/1.7

1 : 2 : 1

C : H : O = 1 : 2 : 1

Empirical formula is CH₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = CH₂O = 12×1 + 2× + 16

Empirical formula mass = 30

n = 180.156 / 30

n = 6

Molecular formula = n (empirical formula)

Molecular formula = 6 (CH₂O)

Molecular formula = C₆H₁₂O₆

5 0

3 years ago

An object has a mass of 15.2 g and a volume of 8.9 mL. <br> What is the density of the object?

Murljashka [212]

Answer:

recordando también que ** 1mL = 1cm ^ 3 **

(como ** 1 dm ^ 3 = 1 L **)

8 0

3 years ago

The diagram shows that the potential energy of the products is lower

german

Answer: D

Explanation:

6 0

2 years ago