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Irina18 [472]
3 years ago
12

If you just want points just say so this can lead me to failing 10th if I don’t pass this quiz so if you don’t know just say so

I understand you want points I just don’t wanna fail Ocean acidification is a consequence that occurs when the equilibrium between CO2
CO
2
concentrations in the ocean and atmosphere starts shifting. What is the pH of pure water?

Question 8 options:

13, basic


7, neutral


4, acidic
Chemistry
1 answer:
aniked [119]3 years ago
6 0

Answer:

13,basic would be your answer!

Explanation:

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The decomposition reaction of carbon disulfide to carbon monosulfide and sulfur is first order with k = 2.80 ✕ ✕ 10−7 sec-1 at 1
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Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

              b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

                          CS_2(g)\rightarrow CS(g)+S(g)

at t=0                    4.83g             0          0

at t=37 days        4.83 - x            x           x

here,

x = amount of CS_2 utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

k=\frac{2.303}{t}log\frac{A_o}{A}

where, k = rate constant

t = time

A_o = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

k=2.80\times10^{-7}sec^{-1}

t = 370 days = 3196800 sec

A_o = 4.83

A = 4.83-x

Putting values in the above equation, we get

2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)

x = 2.85g

Amount of CS_2 remained after 37 days = 4.83 - x

                                                                     = 1.97g

b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

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