Question

How many moles of water can be produced with 4.3 moles of H2 and 5.6 moles of O2? Which reactant is limiting ? How many moles of the excess will be left after the reaction?​

Answer 1

Answer:

4.3 Moles of Water

3.45 moles of O2 is excess.

Explanation:

$2H_{2} + O_{2} -> 2H_{2}O$

2Moles of H2 produce 2Moles of Water

Required O2 moles 4.3/2 = 2.15 moles.

5.6 - 2.15 = 3.45 moles of O2 is excess.