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3 years ago

Aluminum reacts with HCl to produce aluminum chloride and hydrogen gas.

Chemistry

1 answer:

ss7ja [257]3 years ago

7 0

Answer:

Aluminum Reacts With Hydrochloric Acid To Produce Aluminum Chloride And Hydrogen Gas. 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g)What Mass Of H2(g) Is Required From The Reaction Of 0.75 G Of Al(s) With Excess Hydrochloric

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What are six characteristics all living things share

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4 years ago

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What is the molarity of a nitric acid solution if 43.13 mL 0.1000 M KOH solution is needed to neutralize 30.00 mL of the acid so

Leno4ka [110]

Answer:

0.144M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

HNO3 + KOH —> KNO3 + H20

From the equation,

nA = 1

nB = 1

From the question given, we obtained the following:

Ma =?

Va = 30.00mL

Mb = 0.1000M

Vb = 43.13 mL

MaVa / MbVb = nA/nB

Ma x 30 / 0.1 x 43.13 = 1

Cross multiply to express in linear form

Ma x 30 = 0.1 x 43.13

Divide both side by 30

Ma = (0.1 x 43.13) /30 = 0.144M

The molarity of the nitric acid is 0.144M

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3 years ago

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3 years ago

How many significant figures are in the measurement 0.0056 ke?

creativ13 [48]

Question:
how many significant figures are in the measurement 0.0056 ke?
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3 years ago

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2.61 kilograms of water in a container have a pressure of 200 kPa and temperature of 200°C . What is the volume of this containe

Arisa [49]

Answer: The volume of the container is $2.8497m^3$

Explanation:

To calculate the volume of water, we use the equation given by ideal gas, which is:

$PV=nRT$

or,

$PV=\frac{m}{M}RT$

where,

P = pressure of container = 200 kPa

V = volume of container = ? L

m = Given mass of water = 2.61 kg = 2610 g (Conversion factor: 1kg = 1000 g)

M = Molar mass of water = 18 g/mol

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of container = $200^oC=[200+273]K=473K$

Putting values in above equation, we get:

$200kPa\times V=\frac{2610g}{18g/mol}\times 8.31\text{L kPa }\times 473K\\\\V=2849.7L$

Converting this into cubic meter, we use the conversion factor:

$1m^3=1000L$

So, $\Rightarrow \frac{1m^3}{1000L}\times 2849.7L$

$\Rightarrow 2.8497m^3$

Hence, the volume of the container is $2.8497m^3$

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3 years ago