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Angelina_Jolie [31]

1 year ago

9

Could someone please help me with this?A) 2.1 cmB) 1.5 cmC) 1.8 cmD) 2.4 cm

1 answer:

katrin2010 [14]1 year ago

7 0

Answer: It is C I just did this question in math class

Explanation:

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Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these

deff fn [24]

The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

Hrxn = Hproduct

Substituting,

Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

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3 years ago

This formula equation is unbalanced. Pb(NO3)2(aq) + Li2SO4(aq)--> PbSO4(s) + LiNO3(aq). Which coefficient should appear in fr

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<span>Balancing is making sure there are the same number of atoms on either side of the reaction.

Pb(NO3)2 + Li2SO4--> PbSO4 + LiNO3

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List two structures that have similar functions in plants and animals.how are they different

Aleks [24]

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3 years ago

What is the name of the molecule below?

ehidna [41]

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3 years ago

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Nitric oxide (NO) reacts readily with chlorine gas as follows.2 NO(g) + Cl2(g) equilibrium reaction arrow 2 NOCl(g)At 700. K the

Yanka [14]

<u>Answer:</u>

<u>For a:</u> The mixture will need to produce more reactants to reach equilibrium.

<u>For b:</u> The mixture will need to produce more reactants to reach equilibrium.

<u>For c:</u> The mixture will need to produce more products to reach equilibrium.

<u>Explanation</u>:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

The expression of $K_{p}$ for above equation follows:

$K_{p}=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}$ .....(1)

We are given:

Value of $K_p$ = 0.26

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium.

For the given options:

<u>For a:</u>

We are given:

$p_{NOCl}=0.11atm\\p_{NO}=0.16atm\\p_{Cl_2}=0.30atm$

Putting values in expression 1, we get:

$Q_p=\frac{(0.11)^2}{(0.16)^2\times 0.30}=1.57$

As, $K_{p}$ ; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

<u>For b:</u>

We are given:

$p_{NOCl}=0.048atm\\p_{NO}=0.12atm\\p_{Cl_2}=0.10atm$

Putting values in expression 1, we get:

$Q_p=\frac{(0.048)^2}{(0.12)^2\times 0.10}=1.6$

As, $K_{p}$ ; the reaction is reactant favored

Hence, the mixture will need to produce more reactants to reach equilibrium.

<u>For c:</u>

We are given:

$p_{NOCl}=5.20\times 10^{-3}atm\\p_{NO}=0.15atm\\p_{Cl_2}=0.15atm$

Putting values in expression 1, we get:

$Q_p=\frac{(5.20\times 10^{-3})^2}{(0.15)^2\times 0.15}=0.008$

As, $K_{p}>Q_p$ ; the reaction is product favored.

Hence, the mixture will need to produce more products to reach equilibrium.

8 0

3 years ago