Question

The acid dissociation constant for boric acid, h3bo3, is 5.8 x 10-10. calculate the dissociation constant, kb , of the hydrogen borate ion ( hbo32- ).

Answer 1

The answer is 5.8x10^-10. I did the math and checked other sources as well.

Answer 2

Answer: The base dissociation constant for a conjugate base is $1.72\times 10^{-5}$

Explanation:

To calculate the base dissociation constant for the given acid dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant = $5.8\times 10^{-10}$

$K_b$ Base dissociation constant = ?

Putting values in above equation, we get:

$10^{-14}=5.8\times 10^{-10}\times K_b\\\\K_b=0.172\times 10^{-4}=1.72\times 10^{-5}$

Hence, the base dissociation constant for a conjugate base is $1.72\times 10^{-5}$