The given compound is being synthesized by condensing
Acetone and
Pivaldehyde (Trimethylacetaldehyde).
First Acetone is treated with
Base, the base abstracts the mildly acidic proton present at alpha position to carbonyl group. The resulting specie called
enolate act as a nucleophile and attacks on highly reactive aldehyde which upon
dehydration yields the
Aldol Product. The Reaction is as follow,
Answer:
[OH-] = 6.17 *10^-10
Explanation:
Step 1: Data given
pOH = 9.21
Step 2: Calculate [OH-]
pOH = -log [OH-] = 9.21
[OH-] = 10^-9.21
[OH-] = 6.17 *10^-10
Step 3: Check if it's correct
pOH + pH = 14
[H+]*[OH-] = 10^-14
pH = 14 - 9.21 = 4.79
[H+] = 10^-4.79
[H+] = 1.62 *10^-5
6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14
In an experiement things that are changing are called variables.
Within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixturesincluding solutions, alloys, suspensions, and colloids. A solutionis a mixture where one of the substances dissolves in the other. The substance that dissolves is called the solute.