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timurjin [86]
3 years ago
13

2H2O + 2K (s) → 2KOH (1) + 2H2 (g) is an example of which type of reaction?

Chemistry
2 answers:
AlexFokin [52]3 years ago
7 0
Its a single Displacement reaction
Vera_Pavlovna [14]3 years ago
3 0

Answer:

The reaction 2 H₂O + 2 K (s) → 2 KOH (1) + 2H₂ (g) is <u><em>single-displacement (option A)</em></u>

Explanation:

A single-displacement reaction is a reaction in which an element of a compound is substituted by another element involved in the reaction. The general form of a simple substitution reaction is:

AB + C → A +BC

where C and A are pure elements; C replaces A within compound AB to form a new co, placed CB and elementary A.

A single-displacement reaction is characterized by a place of exchange of cations or anions with another to form a new product. A begins as an ion in the solution and appears elementally in the reaction products. In case of reagent C it starts in its elemental form and ends as an ion in an aqueous state forming compound BC.

On the other hand, in a decomposition reaction, a single substance decomposes, producing two or more different substances. The atoms that form a compound are separated to give the products according to the formula:

AB → A + B

Finally, combustion reactions are reactions where oxygen intervenes as a reagent. Oxygen has the ability to combine with various elements to produce oxides, where then oxidation is the combination of oxygen with another substance.

Taking into account all the previously stated definitions, you can see that <u><em>the reaction 2 H₂O + 2 K (s) → 2 KOH (1) + 2H₂ (g) is single-displacement (option A)</em></u>

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What is the best place to find detailed information about a hazardous chemical used in your work area
azamat

Answer:

MSDS  --  Material Safety Data sheet

Explanation:

The full form of MSDS is Material Safety Data sheet. A Material Safety Data Sheet is a document which contains the information related to the potential hazards (fire or reactivity and environmental and health ) and includes how to work or use the chemical product safely.

It is regarded as an essential starting point for development of the complete health as well as safety program. MSDS also contains other information such as the use of the chemical, its storage and also handling and the  emergency procedures that are related to the hazards of the material.

3 0
3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
balandron [24]

Answer:

The final temperature of the water is 22.44°C.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-q_1=q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

q_2=m_2c_2\times (T-T_3)

-q_1=q_2  (Law of Conservation of energy)

-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

The final temperature of the water is 22.44°C.

3 0
3 years ago
Please help me I really need it :(
skad [1K]

Answer: i Honestly don’t know

Explanation:

7 0
3 years ago
Read 2 more answers
Please tell me which one?<br><br>​
vlada-n [284]

Answer:

i think its c

Explanation:

7 0
3 years ago
If a sample of gas has a volume of 100.0ml when the pressure is 50.0kPa, what is volume when the pressure is increased to 400.0k
dalvyx [7]

Answer:

V₂ = 12.5 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial pressure = 50.0 KPa

Final volume = ?

Final pressure = 400.0 KPa

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

50.0 KPa × 100.0 mL = 400 KPa × V₂

V₂ = 5000 KPa.mL/ 400 KPa

V₂ = 12.5 mL

6 0
3 years ago
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