<u>Answer:</u>
a. Oxidising agent: Cl₂
b. Reducing agent: NaBr
c. Oxidised: NaBr
d. Reduced: Cl₂
e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1
f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0
<u>Explanation:</u>
Oxidising agents reduces themselves, oxidising other elements/compounds.
Reducing agents oxidise themselves, reducing other elements/compounds.
Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.
Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.
Answer:
E = 2.05×10⁻²³ J
Explanation:
Given data:
Wavelength of transmission = 9.7 mm (9.7/1000 = 0.0097 m)
Energy of transition = ?
Solution:
9.7 mm (9.7/1000 = 0.0097 m)
9.7×10⁻³ m
Formula:
E = hc/λ
By putting values,
E = 6.63 ×10⁻³⁴ Js × 3×10⁸ m/s / 9.7×10⁻³ m
E = 19.89×10⁻²⁶ J.m / 9.7×10⁻³ m
E = 2.05×10⁻²³ J
47)1-6 and 5&6-8 hope this helps!
