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finlep [7]
3 years ago
6

Carbon obtained from a sample of frozen skin in a glacier is found to have one-half the 14c-to-12c ratio of present-day carbon.

about how old is the skin? the half-life of 14c is 5730

Chemistry
1 answer:
Otrada [13]3 years ago
8 0
Check the attached file for the answer.

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All atoms of the same element have the same what??
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Differentiate the three pictures and explain them briefly.
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2 years ago
What is the frequency and energy per quantum (in Joules) of :
viktelen [127]

(a) f = 5.00 × 10²⁰ Hz, E = 3.32 × 10⁻¹³ J;

(b) f = 1.20 × 10¹⁰ Hz, E = 7.96 × 10⁻²⁴J.

<h3>Explanation</h3>

What's the similarity between a gamma ray and a microwave?

Both gamma rays and microwave rays are electromagnetic radiations. Both travel at the speed of light at 3.00 \times 10^{8}\;\text{m}\cdot\text{s}^{-1} in vacuum.

f = \dfrac{c}{\lambda}

where

  • f is the frequency of the electromagnetic radiation,
  • c is the speed of light, and
  • \lambda is the wavelength of the radiation.

(a)

Convert all units to standard ones.

\lambda = 0.600\;\text{pm} = 0.600 \times 10^{-12} \;\text{m}.

The unit of f shall also be standard.

f = \dfrac{c}{\lambda} = \dfrac{3.00\times 10^{8}\;\text{m}\cdot\text{s}^{-1}}{0.600\times 10^{12}\;\text{m}} = 5.00 \times 10^{20}\;\text{s}^{-1}= 5.00\times 10^{20}\;\text{Hz}.

For each particle,

E = h\cdot f,

where

  • E is the energy of the particle,
  • h is the planck's constant where h = 6.63\times 10^{-34}\;\text{J}\cdot\text{s}^{-1}, and
  • f is the frequency of the particle.

E = h \cdot f = 6.63\times10^{-34}\;\text{J}\cdot\text{s}\times 5.00\times 10^{20}\;\text{s}^{-1} = 3.32\times10^{-13}\;\text{J}.

(b)

Try the steps in (a) for this beam of microwave with

  • \lambda = 2.50 \;\text{cm} = 2.50\times 10^{-2}\;\text{m}.

Expect the following results:

  • f = 1.20\times 10^{10}\;\text{Hz}, and
  • E = 7.96\times 10^{-24}\;\text{J}.
4 0
3 years ago
Use the chemical equation below to answer the following two questions.
umka2103 [35]
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