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vazorg [7]
3 years ago
15

Atoms of which element below are most likely to gain electrons?

Chemistry
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

Carbon and phosphorus

Explanation:

The atoms of carbon and phosphorus are most likely to gain electrons from the given choices .

The reason for this is because, both carbon and phosphorus are non-metals. Most non-metals usually accept electrons.

Metals are usually electron donors .

  • Metals are known for their electropositivity which is their ability to lose electrons.
  • Non-metals are electronegative and will tend to have a strong affinity for electrons.
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What is the boiling point of a 1.5 m aqueous solution of fructose? the boiling point elevation constant of water is 0.515°c/m.
GREYUIT [131]
Answer is: <span>he boiling point of a 1.5 m aqueous solution of fructose is </span>100.7725°C.
The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.<span>
ΔTb -  the boiling point elevation.
Kb - the ebullioscopic constant. of water.
b - molality of the solution.
Kb = 0.515</span>°C/m.
b = 1.5 m.
ΔTb = 0.515°C/m · 1.5 m.
ΔTb = 0.7725°C.
Tb(solution) = Tb(water) + ΔTb.
 Tb(solution) = 100°C + 0.7725°C = 100.7725°C.
5 0
3 years ago
When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J.
dsp73

We have that the work function of the metal

\phi=1.227*10^{-18}J

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy K.E =3.54*10-19 J.

Generally the equation for Kinetic energy    is mathematically given as

KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}

\phi=1.227*10^{-18}J

For more information on this visit

brainly.com/question/12669551?referrer=searchResults

8 0
3 years ago
What does CoH12O6 tell you about the glucose molecule?
Leokris [45]

Answer:

Glucose = C6H12O6

molecular mass = 6(12) + 12(1) + 6(16)

= 72 + 12 + 96

= 180 g

Explanation:

Glucose has a chemical formula of: C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms. ... Glucose is produced during photosynthesis and acts as the fuel for many organisms.

8 0
3 years ago
1-Bromopropane is treated with each of the following reagents. Draw the major substitution product if the reaction proceeds in g
sammy [17]

Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

5 0
3 years ago
Hydrogen is a reactive gas under normal conditions.Based on this property alone, to which group of the periodic table should hyd
denis23 [38]
Even though Hydrogen is originally in group 1, based on this property, we can say it is in group 6.

Because:

Group 6 would mean that it only needs 2 more valence electrons till the octet (8 valence electrons). This would make it reactive, yet, in normal conditions, unlike group 7.
5 0
4 years ago
Read 2 more answers
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