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vazorg [7]
2 years ago
15

Atoms of which element below are most likely to gain electrons?

Chemistry
1 answer:
ruslelena [56]2 years ago
4 0

Answer:

Carbon and phosphorus

Explanation:

The atoms of carbon and phosphorus are most likely to gain electrons from the given choices .

The reason for this is because, both carbon and phosphorus are non-metals. Most non-metals usually accept electrons.

Metals are usually electron donors .

  • Metals are known for their electropositivity which is their ability to lose electrons.
  • Non-metals are electronegative and will tend to have a strong affinity for electrons.
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A burner on a stove produces?
loris [4]

Answer:

thermal energy

Explanation:

7 0
3 years ago
GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

4 0
3 years ago
Fill in the blank
barxatty [35]

<em>Same group element have same</em><em><u> Valence electron</u></em><em> and behave similarly in </em><em><u>Chemistry.</u></em>

<u>Explanation:</u>

For example. First group elements Alkali metals:- H, Li, K, Rb, Cs, Fr

Valance electron will take part in forming a bond with other elements and compound will form. All the above-given elements (H-Fr) have valence electron 1 in outer most 'S' shell. All have electronic configuration S1

Behavior: Since valence electrons are the same so the behavior of all the elements in this group is the same. All are metal (from Li-Fr, except Hydrogen), all are very reactive, does not found in native state in the environment, and all react with water.

4 0
3 years ago
Which of the following describes a chemical property of oxygen
monitta

Which of the following describes a chemical property of oxygen

8 0
2 years ago
A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if
serg [7]
<h3>Answer:</h3>

78.75 K

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P₁ = 500 torr
  • Initial temperature,T₁ = 225 K
  • Initial volume, V₁ = 3.3 L
  • Final volume, V₂ = 2.75 L
  • Final pressure, P₂ = 210 torr                        

We are required to calculate the new temperature, T₂

  • To find the new temperature, T₂ we are going to use the combined gas law;
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K

5 0
3 years ago
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