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3 years ago

Atoms of which element below are most likely to gain electrons?

Chemistry

1 answer:

ruslelena [56]3 years ago

4 0

Answer:

Carbon and phosphorus

Explanation:

The atoms of carbon and phosphorus are most likely to gain electrons from the given choices .

The reason for this is because, both carbon and phosphorus are non-metals. Most non-metals usually accept electrons.

Metals are usually electron donors .

Metals are known for their electropositivity which is their ability to lose electrons.
Non-metals are electronegative and will tend to have a strong affinity for electrons.

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KiRa [710]

Answer:

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3 years ago

When red litmus paper is added to limewater, then what will

Sedbober [7]

Red Litmus paper turns blue

Answer:

$Ca(OH) _2$

Explanation:

In lime water $\red{\bold {RED}}$ litmus paper turns $\blue {\bold {BLUE}}$ because lime water is alkaline.

$formula \: for \: lime \: water : Ca(OH) _2 \\$

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3 years ago

Which will diffuse the most? The particles with the

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Answer:

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Explanation:

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2 years ago

Darwin's theorized that three conditions were necessary for natural selection to occur, which of the following is NOT one of the

Mekhanik [1.2K]

Answer:

The correct option is: stable environment

Explanation:

According to the Darwin's theory, natural selection is the concept by which all the small useful variations of traits are preserved.

According to Darwin, there are three necessary and sufficient conditions for the occurrence of natural selection:

1. struggle for existence

2. variation

3. inheritance

These conditions are said to be necessary because if these conditions are not satisfied then natural selection does not occur.

These conditions are said to be sufficient because if these conditions are satisfied, then natural selection will most definitely occur.

8 0

3 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

Answer: The value of equilibrium constant for the given reaction is 56.61

Explanation:

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 0.1 0.1

At eqllm: 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago