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nadezda [96]
4 years ago
9

You are wrapping a gift with the dimensions shown below. What is the least amount of wrapping paper you need?

Mathematics
2 answers:
yKpoI14uk [10]4 years ago
5 0
That's a wierd gift

find surace area

2 identical side rectangle
2 identical end triangle
1 bottom rectangle

area of trialge=1/2bh
aera of rectangle=legnth tiems width

2 side rectangles are 5 by 10=50
times 2 since 2 of them 50*2=100

end triangles
1/2 times 8 times 3=12
2 of them
12 times 2=24

bottom
8 by 10
80

add everybody

100+24+80=204 in^2
saw5 [17]4 years ago
5 0

Answer:

Step-by-step explanation:

find surace area2 identical side rectangle2 identical end triangle1 bottom rectanglearea of trialge=1/2bhaera of rectangle=legnth tiems width2 side rectangles are 5 by 10=50times 2 since 2 of them 50*2=100end triangles1/2 times 8 times 3=122 of them12 times 2=24bottom8 by 1080add everybody100+24+80=204 in^

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