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3 years ago

Ccording to Newton's Second Law, what effect will doubling the mass of an object have?

Physics

1 answer:

lord [1]3 years ago

4 0

As the mass of an object is increased, the acceleration of the object is decreased.

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Resistance and resistivity are related by a:

Alecsey [184]

Answer:

estan relacionadas por una R XD

Explanation:

7 0

3 years ago

Calculate the force required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

Evgen [1.6K]

Statement:

A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

To find out:

The force required to accelerate the ball.

Solution:

Mass of the ball (m) = 600 g = 0.6 Kg
Initial velocity (u) = 0 m/s [it was at rest]
Final velocity (v) = 14 m/s
Time (t) = 0.1 s

Let the acceleration be a.
We know the equation of motion,
v = u + at

Therefore, putting the values in the above formula, we get
14 m/s = 0 m/s + a × 0.1 s
or, 14 m/s ÷ 0.1 s = a
or, a = 140 m/s²

Let the force be F.
We know, the formula : F = ma

Putting the values in the above formula, we get
F = 0.6 Kg × 140 m/s²
or, F = 84 N

Answer:

The force required to accelerate the ball is 84 N and this force acts along the direction of motion.

Hope you could understand.

If you have any query, feel free to ask.

5 0

3 years ago

The potential energy for a mass on a spring is proportional to the square of which of these quantities? A. mass B. frequency C.

frutty [35]

<h2>Answer:Displacement</h2>

Explanation:

Potential energy is present in a spring because the spring is elongated and some work is done it to elongate it.

The elastic potential energy present in a spring is given by $kx^{2}$

where $k$ is the spring constant.It may vary from spring to spring and $x$ is the displacement of the spring from its equalibrium position.

It is evident from the equation that potential energy in the spring increases as $x^{2}$ increases.

3 0

3 years ago

. A circular wire loop 40 cm in diameter has 100 Ohm resistance and lies in a horizontal plane. A uniform magnetic field points

sergeinik [125]

Answer:

(a) 6.283 Wb (b) 69.11 Wb (c) I = 0.628 A

Explanation:

Given that,

The diameter of the loop, d = 40 cm

Radius, r = 20 cm

Initial magnetic field, B = 5 mT

Final magnetic field, B' = 55 mT

Initial magnetic flux,

$\phi_i=BA\\\\=5\times 10^{-3}\times \pi \times 20^2\\\\=6.283\ Wb$

Final magnetic flux,

$\phi_f=B'A\\\\=55\times 10^{-3}\times \pi \times 20^2\\\\=69.11\ Wb$

Due to change in magnetic field an emf will be generated in the loop. It is given by :

$\epsilon=-\dfrac{d\phi}{dt}\\\\=\phi_f-\phi_i\\\\=69.11-6.283\\\\=62.827\ V$

Let I be the current in the loop. We can find it using Ohm's law such that,

$\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{62.827}{100}\\\\=0.628\ A$

Hence, this is the required solution.

7 0

3 years ago

Which box depicts the tissue level of organization? A) P B) Q C) R D) S

sveta [45]

The right answer is Q).

Explanation:
P) Depicts organ level of organization.
R) Depicts cellular level of organization.
S) Depicts Organ System level of organization.

8 0

3 years ago