Answer:
82.8986 km
Explanation:
Given:
Pressure = 7.00×10⁻¹³ atm
Since , 1 atm = 101325 Pa
So, Pressure = 7.00×10⁻¹³×101325 Pa = 7.09275×10⁻⁸ Pa
Radius = 2.00×10⁻¹⁰ m
Diameter = 4.00×10⁻¹⁰ m (2× Radius)
Temperature = 303 K
The expression for mean free path is:
Boltzmann Constant = 1.38×10⁻²³ J/K
So,
<u>Mean free path = 82.8986×10³ m = 82.8986 km</u>
A low-luminosity star has a small and narrow <u>habitable zone</u>, whereas a high-luminosity star has a large and wide one.
<h3>What is luminosity of a star?</h3>
The radiant power emitted by a light-emitting item over time is measured as luminosity, which is an absolute measure of radiated electromagnetic power (light).
The total quantity of electromagnetic energy released per unit of time by a star, galaxy, or other celestial object is referred to as luminosity in astronomy.
Learn more about low-luminosity star:
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Answer:
When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved? They will move at the same velocity as whichever object was fastest initially. They will move at the same velocity of whichever object was slowest initially.
Explanation:
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<span>Work=effective force x distance = 300cos36. 100 ft.lb.</span>
Answer:
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