Answer:
1) 950 mL
2) 625 mmHg
3) 426 mL
Explanation:
1) This is the relationship between pressure and volume. This relationship looks like this:
P1*V1 = P2*V2
This means the first pressure times the initial volume is equal to the second pressure times the second volume. We are solving for the second volume. First, convert the mmHg to atm and the mL to L.
1 L * 1 atm = 1.053 atm * X
X = 0.95 L or 950 mL
2) This is the same concept as the last one. :) We don't have to convert the mmHg to atm since the answer wants it in mmHg.
750 mmHg * 0.25 L = 0.3 L * X
X = 625 mmHg
3) The relationship between volume and temperature is similar to the one between pressure and temperature (like the problem in your last question). Remember to convert degrees C to Kelvin and mL to L.
V1 / T1 = V2 / T2
0.4 L / 303 K = X / 323 K
X = 0.426 L pr 426 mL
These problems become much easier once you learn the relationships between the different variables (temp, pressure, volume, etc.) When you have a problem like this, I like to first determine what relationship I am dealing with and then write out what I have and what I am solving for. This helps with organizing the problem. Then just solve it like a normal algebra problem. Always remember to convert temp to Kelvin, mL to L, and pressure to atm (unless it wants it in a different unit, then just make sure all the units match).
Good luck with you studies! :)
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
So we cancel out the moles of NaCl to obtain:
Best regards!
PPRR, PpRR, PPRr, and PpRr
Answer:
The sp³ orbital hybridization has 25% s-character and 75% p-character.
Explanation:
Hybridization refers to the process of mixing of a given number atomic orbitals to form equal number of new hybrid orbitals. The three types of hybrid orbitals are sp³, sp² and sp.
The<u> four sp³ hybridized orbitals</u> are formed by the mixing of <u>one s orbital and three p orbitals.</u>
Thus s-character in a sp³ hybridized orbital = (1÷4)×100 = 25%
and p-character in a sp³ hybridized orbital = (3÷4)×100 = 75%
<u>Therefore, the sp³ orbital hybridization has 25% s-character and 75% p-character.</u>
Answer: No charge (0)
Explanation:
The atom has a proton of 22 and electron number of 19. This means the element has lost 3 electrons. Therefore, the net charge is +3.
So, if this atom gains 3 more electrons, the net charge would be zero (neutral).
The total number of electron would now be 22 which is the same as the proton number.
This implies the atom is now in an unreacted state or ground state.
