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2 years ago

9

The physician has ordered 1.0 g of tetracycline to be given every six hours to a patient. If your stock on hand is 500-mg tablet

s, how many will you need for one day's treatment?

1 answer:

Doss [256]2 years ago

8 0

8 tablets. To get 1 gram you would have to give 2 tablets every 6 hours. In 24 hours you would give 8 tablets (500 mg = .5 grams)

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Consumption of a synthetic material being increased, leads to an associated negative impacts to Earth required to produce it is a True statement.

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There are the materials which are made by humans through chemical synthesis which are usually done in factories.

The production of this type of materials leads to the emission of chemicals and other gases which are harmful and negatively impacts the environment.

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1 year ago

Someone please help me with one of them

EastWind [94]

Explanation:

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2 years ago

What is a non-example of Volume? A. The glass is half full is an example of volume. B.The glass is half empty is an example of n

Vladimir [108]

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2 years ago

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1 Which of the following is an example of periodicity?

Mademuasel [1]

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1 year ago

The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

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2 years ago